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4 years ago

When you speak or sing, you force air through your ?

Physics

1 answer:

zaharov [31]4 years ago

6 0

You force air from your lungs up through your larynx which is commonly called the voicebox

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A 6.00-kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

timofeeve [1]

Answer:

The magnitude of F when t=4 s=146.64 N

Explanation:

We are given that

Mass of crate,m=6.00 kg

Height of crate above its initial position is given by

$y(t)=(2.80 m/s)t+(0.610 m/s^3)t^3$

We have to find the magnitude of F when t=4.00 s

Differentiate w.r.t t

$\frac{dy}{dt]=2.8+3(0.61)t^2$

$\frac{d^2y}{dt^2}=6(0.61)t$

$a(t)=\frac{d^2y}{dt^2}=6(0.61)t m/s$

$a(4)=6(0.61)(4)=14.64 m/s^2$

Now, magnitude of force

$F=m(a+g)=6(14.64+9.8)=146.64N$

Hence, the magnitude of F when t=4 s=146.64 N

4 0

3 years ago

Which two particles are found in the center of an atom

VikaD [51]

the two particles that are found in the center of an atom are protrons and neutrons.

6 0

3 years ago

A ball is thrown upwards from the edge of a cliff. The horizontal velocity and vertical velocity are both 20m/s the distance fro

german

Answer:

20m

6.9s

Explanation:

The vertical velocity of the ball is 20m/s. We can calculate the kinetic energy which gets transferred to potential energy once it gets to the top.

$E_k = E_p$

$0.5mv^2 = mgh$

$h = \frac{0.5v^2}{g}$

we can subtitute v = 20m/s and g = 10m/s2

$h = \frac{0.5*20^2}{10} = 20 m$

So the ball could go 20m high from the child hand, or 120m fro the bottom of the cliff.

The time it takes for the ball to travels to the top is the time it takes for it to decelerate from 20m/s to 0m/s with gravitational deceleration g = 10m/s2

t = v / g = 20 / 10 = 2s

Then the ball will start accelerating down ward with a constant acceleration of g = 10m/s. In order to cover distance d of 120m from the top to the bottom of the cliff

$d = \frac{gt_2^2}{2}$