If 2x + 6y = 16, which of the following expressions represents x in terms of y?

Joe and Maggie are working at McDonald's joe make $8.50 per hour while Maggie makes $9.00 per hour. How much would they both mak

3241004551 [841]

The awnser is 8.50x +9x. i hope this helps

5 0

3 years ago

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Can you help me solve the Missing Tangents? 7-15

slavikrds [6]

You know from SOH CAH TOA that
.. tan(θ) = Opposite/Adjacent

Then the relations for any of these variables will be
.. Opposite = Adjacent * tan(θ)
.. Adjacent = Opposite / tan(θ)
.. θ = arctan(Opposite/Adjacent)

7. x is opposite.
.. x = (30 cm)*tan(26°) ≈ 14.63 cm

8, 9, 10, 14. x is opposite

11. x = arctan(30/60) ≈ 26.57°

12, 13, 15. x is the angle

6 0

3 years ago

On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant

VladimirAG [237]

Answer:

a) $2\frac{7}{12}$ kg of plant food did Sheldon have left.

b) She need is $\frac{43}{12}$ kg and she don't have enough to left.

Step-by-step explanation:

Given : On Sunday, Sheldon bought $4\frac{1}{2}$ kg of plant food. He used $1\frac{2}{3}$ kg on his strawberry plants and used $\frac{1}{4}$ kg for his tomato plants.

To find :

a) How many kilograms of plant food did Sheldon have left? Write one or more equations to show how you reached your answer.

Solution :

Sheldon bought plant food $4\frac{1}{2}=\frac{9}{2}$ kg.

He used strawberry plants $1\frac{2}{3}=\frac{5}{3}$ kg.

He used tomato plants $\frac{1}{4}$ kg

Kilograms of plant food did Sheldon have left is given by,

$L=\frac{9}{2}-(\frac{5}{3}+\frac{1}{4})$

$L=\frac{9}{2}-\frac{23}{12}$

$L=\frac{54-23}{12}$

$L=\frac{31}{12}$

$L=2\frac{7}{12}$

Therefore, $2\frac{7}{12}$ kg of plant food did Sheldon have left.

b) Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will he need? Does he have enough left to do so?

Solution :

Sheldon wants to feed his strawberry plants 2 more times.

i.e. Strawberry plants used is $2(\frac{5}{3})=\frac{10}{3}$ kg.

His tomato plants one more time i.e. $\frac{1}{4}$ kg.

Total plant she need is $\frac{10}{3}+\frac{1}{4}=\frac{43}{12}$

As $\frac{31}{12}$

No she don't have enough to left.

4 0

3 years ago

A steamer travels 36 km upstream and 32 km downstream in 6.5 hours. The same steamer travels 4 km upstream and 40 km downstream

rewona [7]

Answer:

The streamer's speed in still water is 90.23 km/h while the stream's speed is 33.33 km/h

Step-by-step explanation:

Let v = streamer's speed in still water and v' = stream's speed. His speed upstream is V = v + v' and his speed downstream is V' = v - v'.

Since he travels 36 km upstream, the time taken is t = 36/V = 36/(v + v').

he travels 32 km downstream, the time taken is t' = 32/V' = 32/(v - v')

The total time is thus t + t' = 36/(v + v') + 32/(v - v')

Since the whole trip takes 6,5 hours,

36/(v + v') + 32/(v - v') = 6.5 (1)

Multiplying each term by (v + v')(v - v'), we have

(v + v')(v - v')36/(v + v') + (v + v')(v - v')32/(v - v') = 6.5(v + v')(v - v') (1)

(v - v')36 + (v + v')32 = 6.5(v + v')(v - v') (1)

36v - 36v' + 32v + 32v' = 6.5(v² + v'²)

68v - 4v' = 6.5(v² + v'²) (2)

Also he travels 4 km upstream, the time taken is t" = 4/V = 4/(v + v').

he travels 40 km downstream, the time taken is t'" = 40/V' = 40/(v - v')

The total time is thus t" + t'" = 4/(v + v') + 40/(v - v')

Since the whole trip takes 180 minutes = 3 hours,

4/(v + v') + 40/(v - v') = 3 (3)

Multiplying each term by (v + v')(v - v'), we have

(v + v')(v - v')4/(v + v') + (v + v')(v - v')40/(v - v') = 3(v + v')(v - v') (1)

(v - v')4 + (v + v')40 = 3(v + v')(v - v') (1)

4v - 4v' + 40v + 40v' = 3(v² + v'²)

44v - 36v' = 3(v² + v'²) (4)

Dividing (2) by (4), we have

(68v - 4v')/(44v - 36v') = 6.5(v² + v'²)/3(v² + v'²)

(68v - 4v')/(44v - 36v') = 6.5/3

3(68v - 4v') = 6.5(44v - 36v')

204v - 12v' = 286v - 234v'

204v - 286v = 12v' - 234v'

-82v = -222v'

v = -222v'/82

v = 111v'/41

Substituting v into (2), we have

68v - 4v' = 6.5(v² + v'²)

68(111v'/41) - 4v' = 6.5[(111v'/41)² + v'²]

[68(111/41) - 4]v' = 6.5[(111/41)² + 1]v'²

[7548/41 - 4]v' = 6.5[12321/1681 + 1]v'²

[(7548 - 164)/41]v' = 6.5[(12321 + 1681)/1681]v'²

[7384/41]v' = 6.5[14002/1681]v'²

[7384/41]v' = [91013/1681]v'²

[91013/1681]v'² - [7384/41]v' = 0

([91013/1681]v' - [7384/41])v' = 0

⇒ v' = 0 or ([91013/1681]v' - 7384/41) = 0

⇒ v' = 0 or [91013/1681]v' - 7384/41) = 0

⇒ v' = 0 or v' = 7384/41 × 16841/91013

⇒ v' = 0 or v' = 180.097 × 0.185

⇒ v' = 0 or v' = 33.33 km/h

Since v' ≠ 0, v' = 33.33 km/h

Substituting v' into v = 111v'/41 = 111(33.33 km/h)/41 = 3699.63 km/h ÷ 41 = 90.23 km/h

So, the streamer's speed in still water is 90.23 km/h while the stream's speed is 33.33 km/h

5 0

2 years ago

What is the average of 5, 11, 12, and 8?

AURORKA [14]

Answer:

11.5

Good Luck

4 0

2 years ago

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