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Alborosie
3 years ago
9

What is the molarity of HCl found in a titration where 50 ml of HCl is titrated with 50 ml of .1 M NaOH? Needs to be answered as

ap rocky
Chemistry
1 answer:
Aneli [31]3 years ago
7 0

0.1 mol/L . The concentration of the HCl is 0.1 mol/L

a) Write the <em>balanced chemical equation </em>

HCl + NaOH → NaCl + H2O

b) Calculate the <em>moles of NaOH </em>

Moles of NaOH = 0.050 L NaOH x (0.1 mol NaOH/1 L NaOH)

= 0.0050 mol NaOH

c) Calculate the <em>moles of HCl </em>

Moles of HCl = 0.0050 mol NaOH x (1 mol HCl/1 mol NaOH)

= 0.0050 mol HCl

d) Calculate the <em>molar concentration</em> of the HCl

<em>c</em> = moles/litres = 0.0050 mol/0.050 L = 0.1 mol/L

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The final answer is -322, 320 Joules. The solution for the problem is:

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Which equation is used to help form the combined gas law? mc009-1. Jpg mc009-2. Jpg mc009-3. Jpg mc009-4. Jpg.
Luba_88 [7]

The combined gas law equation has been \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}.

The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.

In an ideal gas the equation has been given as:

PV=nRT

Where, <em>P </em>has been the pressure of the gas

<em>V </em>has been the volume of the gas

<em>n </em>has been the moles of the gas

<em>R </em>has been a constant

<em>T </em>has been the temperature of the gas

The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

For more information about combined gas law, refer to the link:

brainly.com/question/13154969

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An object's weight would affect the amount of friction it causes. (true)
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3 years ago
A Helium gas in a tube with a volume of 9.583 L under pressure of 4.972 atm at 31.8 c
andre [41]

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 4.972 atm

V= 9.583 L

n=?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=31.8 +273= 304.8 K

Putting value in the given equation:

\frac{PV}{RT}=n

n= \frac{4.972 \;atm\; X \;9.583 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 304.8}

Moles = 1.905 moles

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

Learn more about the ideal gas here:

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#SPJ1

3 0
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