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lapo4ka [179]
2 years ago
15

If you had a pot of boiling water that is loosing volume is that at equilibrium? What are some things you can do to a pot of boi

ling water to adjust its equilibrium?
Chemistry
1 answer:
ki77a [65]2 years ago
8 0

Answer:

are you rich in points brother ? or sister ?

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What would be the volume in millilitres of a blood sample of 2.15 microliters (ul)?​
Zanzabum

2.15 x 10⁻³mL

Explanation:

Given parameter:

    Volume of blood sample in uL = 2.15uL

Conversion           uL → mL

   micro- and milli-  are both prefixes of sub-units.

liter is a unit of volume of a substance.

       micro - is 10⁻⁶

       milli- is of the order 10⁻³

The problem is converting from micro to milli:

     if we multiply  10⁻⁶ by 10³ we would have our milli;

  1000uL = 1mL

  2.15uL :   2.15uL x \frac{1mL}{1000uL} = 2.15 x 10⁻³mL

learn more:

Volume brainly.com/question/5055270

#learnwithBrainly

4 0
3 years ago
Calculate the standard enthalpy of formation of NOCl(g) at 25 ºC, knowing that the standard enthalpy of formation of NO(g) at th
stepan [7]

Answer:

The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol

Explanation:

The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:

Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants

In this case, you have:  2 NOCl(g) → 2 NO(g) + Cl₂(g)

So, ΔH=2*H_{NO} +H_{Cl_{2} }-2*H_{NOCl}

Knowing:

  • ΔH= 75.5 kJ/mol
  • H_{NO}= 90.25 kJ/mol
  • H_{Cl_{2} }= 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound  the chlorine Cl₂)
  • H_{NOCl}=?

Replacing:

75.5 kJ/mol=2* 90.25 kJ/mol + 0 - H_{NOCl}

Solving

-H_{NOCl}=75.5 kJ/mol - 2*90.25 kJ/mol

-H_{NOCl}=-105 kJ/mol

H_{NOCl}=105 kJ/mol

<u><em>The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol</em></u>

8 0
2 years ago
Is clear water pumped from a deep aquifer a pure substance?
Alexandra [31]

The substance which has definite composition with definite physical and chemical properties is said to be pure substance. These substances are not separated by the different physical techniques such as filtration, distillation, evaporation etc.

The clear water pumped from a deep aquifer is a pure substance because water is a pure compound which consist of constant single type of atoms or group of atoms and water has specific value of boiling and melting point. Water is also not separated into units or constituents by physical technique.

Hence, clear water pumped from a deep aquifer is a pure substance.


4 0
2 years ago
Read 2 more answers
23.9 km + 15 km
Ugo [173]

Answer:

the original answer is 38.9km (3sf)

4 0
3 years ago
Circle the letter next to each sentence that is true concerning the compressibility of gases. a. The large relative distances be
Anuta_ua [19.1K]

Answer:

The large relative distances between particles in a gas means that there is considerable empty space between the particles.

The assumption that particles in a gas are relatively far apart explains gas compressibility.

Compressibility is a measure of how much the volume of matter decreases under pressure.

Energy is released by a gas when it is compressed

Explanation:

The kinetic molecular theory establishes that gases are composed of molecules. These molecules of gas are far apart from each other hence there is a considerable empty space between the gas molecules. As a result of these empty spaces between gas molecules, it is possible to compress a gas.

Compressibility is defined as a measure of how much the volume of matter decreases under pressure. When a gas is compressed, work is done on the gas and energy is evolved hence the gas heats up.

6 0
3 years ago
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