0.182 is the value of the equilibrium constant of the reverse reaction.
Given reaction i.e. Forward reaction
4A + B = 3C
If we reverse this reaction, the equation becomes
3C = 4A + B
Now, the equilibrium-constant statement for the reverse reaction is the opposite of the equilibrium-constant expression for the forward reaction.
Equilibrium constant = [A]⁴ × [B] / [C]³
The concentrations can be used to compute K(reverse) once the formula for the equilibrium constant for the reverse reaction has been established.
Conc. of A = 1.01 M
Conc. of B = 1.51M
Conc. of C = 2.05 M
Kc for reverse reaction = [1.01]⁴ × [1.51]/ [2.05]³
= 0.182
Hence, 0.182 is the value of the equilibrium constant of the reverse reaction.
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Answer:
∆G = 35 KJ
Explanation:
The given data are as follows;
Gastric juice pH = 1.5
Blood plasma pH = 7.4
Temperature = (37 + 273) K = 310 K
However, pH = -log [H+]
Therefore, [H+] = 10^-pH
At pH of 1.5, [H+] = 10^-1.5 = 3.16 × 10^-2 M
At pH of 7.4, [H+] = 10^-7.4 = 3.98 × 10^-8 M
Using ∆G = RTln(C2/C1)
Where R = 8.314 J/mol/K;
T = 310 K;
C2 (concentration inside) = 3.16 × 10^-2 M;
C1 (concentration outside) = 3.98 × 10^-8 M
∆G = 8.314 × 310 × ln(3.16 × 10^-2 / 3.98 × 10^-8)
∆G = 35012.74
Therefore, ∆G = 35 KJ
The charges should balance to 0
Check the circled atoms in the attached diagram
Explanation:
The circled options all belongs to the same elements. They are simply isotopes.
Since:
Red ball = protons
Yellow ball = neutron
Blue ball = electron
The protons are positively charged and with the neutrally charged neutrons they both occupy the vicinity of the nucleus of an atom.
Electrons moves round the nucleus in orbits.
Atoms of the same elements have the same number of protons.
The circled options all have two protons.
The atoms only differ in the number of neutrons which signifies that they are merely isotopes.
More descriptively, the atoms are Helium atoms.
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Isotope brainly.com/question/4551913
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