Please help me. I'll give brainliest. I am stuck. True or false Q.

Consider the overall reaction: 2 X2Y + Z2 ⇌ 2 X2YZ which has an experimentally determined rate law of: rate= k[X2Y][Z2]. Which o

enyata [817]

Answer : The correct possible mechanisms for the reaction is:

Step 1 : $X_2Y+Z_2\rightarrow X_2YZ_2$ (slow)

Step 2 : $X_2YZ_2+X_2Y\rightarrow 2X_2YZ$ (fast)

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the overall reaction,

$2X_2Y+Z_2\rightarrow 2X_2YZ$

The given expression of rate law for this reaction is,

$Rate=k[X_2Y][Z_2]$

Now we have to determine the possible mechanisms for the reaction.

The rate law expression for overall reaction should be in terms of $X_2Y$ and $Z_2$ .

As we know that the slow step is the rate determining step.

Option 1 :

Step 1 : $2X_2Y+Z_2\rightarrow 2X_2YZ$ (slow)

The expression of rate law for this reaction will be,

$Rate=k[X_2Y]^2[Z_2]$

Option 2 :

Step 1 : $X_2Y+Z_2\rightarrow X_2YZ+Z$ (fast)

Step 2 : $X_2Y+Z\rightarrow X_2YZ$ (slow)

The rate law from the slow step 2 is,

$Rate=K'[X_2Y][Z]$ .............(1)

Now applying steady state approximation for $Z$ , we get:

$\frac{d[Z]}{dt}=K"[X_2Y][Z_2]$ .........(2)

Now put equation 2 in 1, we get:

$Rate=K'K"[X_2Y]^2[Z_2]$

$K'K"=K$

The rate law expression will be:

$Rate=K[X_2Y]^2[Z_2]$

Option 3 :

Step 1 : $X_2Y+Z_2\rightarrow X_2YZ_2$ (slow)

Step 2 : $X_2YZ_2+X_2Y\rightarrow 2X_2YZ$ (fast)

The expression of rate law for this reaction will be,

$Rate=k[X_2Y][Z_2]$

Option 4 :

Step 1 : $2X_2Y\rightarrow X_4Y_2$ (fast)

Step 2 : $X_4Y_2+Z_2\rightarrow 2X_2YZ$ (slow)

The rate law from the slow step 2 is,

$Rate=K'[X_4Y_2][Z_2]$ .............(1)

Now applying steady state approximation for $X_4Y_2$ , we get:

$\frac{d[X_4Y_2]}{dt}=K"[X_2Y]^2$ .........(2)

Now put equation 2 in 1, we get:

$Rate=K'K"[X_2Y]^2[Z_2]$

$K'K"=K$

The rate law expression will be:

$Rate=K[X_2Y]^2[Z_2]$

Option 5 :

Step 1 : $Z_2\rightarrow Z+Z$ (slow)

Step 2 : $X_2Y+Z\rightarrow X_2YZ$ (fast)

Step 3 : $X_2Y+Z\rightarrow X_2YZ$ (fast)

The rate law expression will be:

$Rate=K[Z_2]$

From the given options we conclude that the only option 3 is the correct possible mechanisms for the given reaction.

Hence, the correct possible mechanisms for the reaction is:

Step 1 : $X_2Y+Z_2\rightarrow X_2YZ_2$ (slow)

Step 2 : $X_2YZ_2+X_2Y\rightarrow 2X_2YZ$ (fast)

7 0

3 years ago

What is the classification of clouds based on?

Rus_ich [418]

Cloud level (ft)Cloud type

High clouds (CH)

Base usually 20,000 ft or above, over British Isles

CirrusCirrocumulusCirrostratus

Medium clouds (CM)

Base usually between 6,500 and 20,000 ft over British Isles.

AltocumulusAltostratusNimbostratus

Low clouds (CL)

Base usually below 6,500 ft over British Isles.

hope this helps!

8 0

3 years ago

Read 2 more answers

An object has a density of 16.3 g/mL and a volume of 0.46 L. Calculate the

deff fn [24]

Answer:

16.53 pounds

Explanation:

this type of problem needs convertion method we need to convert from grams to pound.

3 0

3 years ago

In photosynthesis what form of energy is sunlight converted to

Schach [20]

Photosinthisises equation is carbon dioxide + water ⇒ glucose (suger) + water
the light is needed to react with the CO² to create the oxygen needded

3 0

4 years ago

What is the density (in g/L) of a gas with

viva [34]

Answer:

2.22 g/L

Explanation:

There's a relationship using the ideal gas law between molar mass and density: $MM=\frac{dRT}{P}$ , where MM is the molar mass, d is the density, R is the gas constant, T is the temperature, and P is the pressure.

We know from the problem that MM = 32.49 g/mol, T = 458 Kelvin, and P = 2.569 atm. The gas constant, R, in terms of the units atm and Kelvin is 0.08206. Let's substitute these values into the formula:

$MM=\frac{dRT}{P}$

$32.49g/mol=\frac{d*0.08206*458K}{2.569atm}$

Solve for d:

d * 0.08206 * 458 K = 32.49 * 2.569

d = (32.49 * 2.569) / (0.08206 * 458 K) ≈ 2.22 g/L

The answer is thus 2.22 g/L.

~ an aesthetics lover

4 0

4 years ago