Answer:
∆G = 35 KJ
Explanation:
The given data are as follows;
Gastric juice pH = 1.5
Blood plasma pH = 7.4
Temperature = (37 + 273) K = 310 K
However, pH = -log [H+]
Therefore, [H+] = 10^-pH
At pH of 1.5, [H+] = 10^-1.5 = 3.16 × 10^-2 M
At pH of 7.4, [H+] = 10^-7.4 = 3.98 × 10^-8 M
Using ∆G = RTln(C2/C1)
Where R = 8.314 J/mol/K;
T = 310 K;
C2 (concentration inside) = 3.16 × 10^-2 M;
C1 (concentration outside) = 3.98 × 10^-8 M
∆G = 8.314 × 310 × ln(3.16 × 10^-2 / 3.98 × 10^-8)
∆G = 35012.74
Therefore, ∆G = 35 KJ
