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Llana [10]
3 years ago
9

How long must a flute be in order to have a fundamental frequency of 262 Hz (this frequency corresponds to middle C on the evenl

y tempered chromatic scale) on a day when air temperature is 20.0°C ? It is open at both ends.

Physics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

L=0.654 m

Explanation:

<u>Concepts and Principles  </u>

1- The speed of sound in air is expressed as a function of the temperature of air as follows:  

 v=(331 m/s)√(1+T_C/273°C)                        (1)

where 331 m/s is the speed of sound in air at temperature 0°C and Tc is the temperature of air in Celsius.  

<u>Standing Wave Patterns in Pipes:  </u>

A pipe open at both ends can have standing wave patterns with resonant frequencies:  

f=v/λ=nv/2L                     n=1,2,3.........

where v is the speed of sound in air.  

<u>Given Data </u>

f_1 (fundamental frequency of the flute) = 262 Hz

T (temperature of the air) = 20°C  

The flute is open at both ends.  

<u>Required Data </u>

We are asked to determine the length of the tube.  

<u>Solution</u><u>  </u>

The speed of sound in air at temperature T = 20°C is found from Equation (1):

 v=(331 m/s)√(1+T_C/273°C)  

 =342.91 m/s

The fundamental frequency of the flute is found by substituting n = 1 into Equation (2):  

f=v/2L

Solve for L:  

L=v/2f_1

L=0.654 m

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Answer:

E_y=1175510.2\ N.C^{-1}

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Explanation:

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diagonal=74.25\cm=0.7425\ m

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Now, electric field due to charges is given as:

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<u>For charge q_1 we have the field lines emerging out of the charge since it is positively charged:</u>

E_1=9\times 10^9\times \frac{45\times 10^{-6}}{0.3712^2}

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<u>Force by each of the charges at the remaining corners:</u>

E_2=E_3=E_4=9\times 10^9\times \frac{27\times 10^{-6}}{0.3712^2}

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<u> Now, net electric field in the vertical direction:</u>

E_y=E_1-E_4

E_y=1175510.2\ N.C^{-1}

<u>Now, net electric field in the horizontal direction:</u>

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E_y=0\ N.C^{-1}

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A. Medium 1 is air. The refractive index of air is 1.0003. Refractive index is a measure of the bending of a ray of light when passing from one medium to another. If i is the angle of incidence of a ray in vacuum and r is the angle of refraction, the refractive index n is defined as the ratio of the sine angle of incidence to the sine of the angle of refraction; that is, n= sin i/ sin r. Refractive index may also be given by the velocity of light in medium 1 divided by the velocity of light in medium 2.


b. In this case the refractive index = sin 72.5/sin 39.6 
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Hence the refractive index of medium 2 is 1.4967. 
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3 years ago
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Answer:

3.16097\times 10^{-8}\ C

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As the forces balance themselves we have the equations

Tcos30=mg

Tsin30=Eq

Dividing the equations we get

tan30=\dfrac{Eq}{mg}\\\Rightarrow E=\dfrac{mgtan30}{q}\\\Rightarrow E=\dfrac{7.1\times 10^{-3}\times 9.81tan30}{0.161\times 10^{-6}}\\\Rightarrow E=249770.33291\ N/C

Electric field is given by

E=\dfrac{Q}{A\epsilon}\\\Rightarrow Q=EA\epsilon\\\Rightarrow Q=249770.33291\times 0.0143\times 8.85\times 10^{-12}\\\Rightarrow Q=3.16097\times 10^{-8}\ C

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9.8 =  10.83² A

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3 years ago
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