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3 years ago

I flow from a warmer object to a cooler object until both objects are the same temperature what am I?

2 answers:

5 0

If you flow from a warmer object to a cooler object until they are both the same temp then you are heat. because heat flows from warm to cool until it reaches thermal equilibrium (when they are the same temp)

jok3333 [9.3K]3 years ago

4 0

HEAT flows from a warmer object to a cooler object until both objects are the same temperature. The answer is heat!

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Which oftthe following is the least reliable source of background information for a scientific project? General internet site, g

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General internet site

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2 years ago

The image shows water passing through a barrier.

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It is diffraction

Explanation:

The opening is the aperture

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3 years ago

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3 years ago

A 3kg object moving at 4 m/s encounters a 20 N resistive force over a duration of 0.20 seconds. The impulse experienced by this

WITCHER [35]

Answer:

the impulse experienced by this object is 4 Ns

Explanation:

Given;

mass of the object, m = 3 kg

velocity of the object, v = 4 m/s

resistive force, F = 20 N

duration of impact, t = 0.2 s

The impulse experienced by this object is calculated as follows;

J = F x t

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J = 4 Ns

Therefore, the impulse experienced by this object is 4 Ns

3 0

3 years ago

When some stars use up their fuel, they undergo a catastrophic explosion called a supernova. This explosion blows much or all of

algol13

Answer:

0.0768 revolutions per day

Explanation:

R = Radius

$\omega$ = Angular velocity

As the mass is conserved the angular momentum is conserved

$I_1\omega_1=I_2\omega_2\\\Rightarrow \frac{I_1}{I_2}=\frac{\omega_2}{\omega_1}$

Moment of intertia for solid sphere

$I_1=\frac{2}{5}MR^2\\\Rightarrow I_1=0.4MR^2$

Moment of intertia for hollow sphere

$I_2=\frac{2}{3}M(4.3R)^2\\\Rightarrow I_2=12.327MR^2$

Dividing the moment of inertia

$\frac{I_1}{I_1}=\frac{0.4MR^2}{12.327MR^2}\\\Rightarrow \frac{I_1}{I_2}=0.032$

From the first equation

$\omega_2=\omega_1\frac{I_1}{I_2}\\\Rightarrow \omega_2=2.4\times 0.032\\\Rightarrow \omega_2=0.0768\ rev\day$

The angular velocity, in revolutions per day, of the expanding supernova shell is 0.0768 revolutions per day

8 0

3 years ago