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4 years ago

I flow from a warmer object to a cooler object until both objects are the same temperature what am I?

2 answers:

5 0

If you flow from a warmer object to a cooler object until they are both the same temp then you are heat. because heat flows from warm to cool until it reaches thermal equilibrium (when they are the same temp)

jok3333 [9.3K]4 years ago

4 0

HEAT flows from a warmer object to a cooler object until both objects are the same temperature. The answer is heat!

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Why does a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude

inna [77]

Answer:

According to your question although I think an object undergoing uniform circular motion is moving with a constant speed. Nevertheless, it is accelerating due to its change in direction. The direction of the acceleration is inwards,therefore a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude.

3 0

3 years ago

When an electric current flows through a long conductor, each free electron moves

ki77a [65]

A. through a relatively short distance.

The speed is actually called the drift speed of the electron.

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3 years ago

A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long

Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

$W=-\mu mg\times l$

Put the value into the formula

$W=-0.30\times62\times9.8\times3.50$

$W=-637.98\ J$

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

$K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}$

$\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}$

Final potential energy is zero

So, $\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2$

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl$

Put the value into the formula

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50$

$v_{2}=\sqrt{2\times55.915}$

$v_{2}=10.57\ m/s$

The speed of skier is 10.57 m/s.

Hence, (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0

3 years ago

Which is not a benefit of stretching? decreased flexibility improved tissue strength decreased chance of injury relief for tense

dmitriy555 [2]

Decreased flexibility

3 0

3 years ago

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in a series circuit, how does the voltage supplied by the battery compare to the voltages on each load?

kozerog [31]

Answer:

In a series circuit, how does the voltage supplied by the battery compare to the voltage on each load? The voltage of the battery is equal to the voltage of each load added together. ... The voltage across the two resistors must both have the same voltage of the battery.

Explanation:

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4 0

3 years ago

Read 2 more answers