Answer:
a) a = 4.9 m / s², N = 16.97 N and b) F = 9.8 N
Explanation:
a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry
sin 30 = Wx / W
cos 30 = Wy / W
Wx = W sin30
Wy = W cos 30
Let's write the equations on each axis
X axis
Wx = ma
Y Axis
N- Wy = 0
N = Wy = mg cos 30
N = 2.0 9.8 cos 30
N = 16.97 N
We calculate the acceleration
a = Wx / m
a = mg sin 30 / m
a = g sin 30
a =9.8 sin 30
a = 4.9 m / s²
b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component
F -Wx = 0
F = Wx
F = m g sin 30
F = 2.0 9.8 sin 30
F = 9.8 N
Both
in the domestic and international guidelines tell that when two power-driven
vessels are crossing so as to contain risk of collision, the vessel which has
the other on her starboard side (the give-way vessel) must keep out of the way.
If
you are the give-way vessel, it is your responsibility to avoid a collision. Normally,
this means you must change speed or direction to cross behind the other vessel
which is the stand-on vessel.
At
evening, when you perceive a red light crossing right-to-left in front of you,
you need to change your course. But if you perceive a green light crossing from
left-to-right, you are the stand-on vessel, and should maintain course and
speed.
The leading situations of collision risk are meeting head-on, overtaking, and crossing. When one of two vessels is to keep out of the way (give-way vessel), the other, the stand-on vessel, must uphold course and speed.
Considering that we are talking about a stepdown transformer, and a turn ration of 1:24
Then
Vsecondary coil = 120 V / 24 = 5V
(But lets remember that the power must be conserved in the transformer, so the voltage is 24 times less, but the current is 24 times higher)
It provides 5 volts to operate the player or charge the batteries
