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3 years ago

using Le Chanteliers principle what will happen and why when NaOH is introduced into iron(III) thicyanate ion equilibrium system

Chemistry

1 answer:

viktelen [127]3 years ago

5 0

Answer:

More [FeSCN]²⁺ will be consumed shifting the reaction to the left.

Explanation:

Th equilibrium equation for iron(III) thiocyanate ion is:

Fe³⁺ + SCN⁻ ⇄ [FeSCN]²⁺

When NaOH is introduced into the equilibrium system, part of the OH⁻ ions react with the Fe³⁺ ions in solution, as per the chemical equation:

Fe³⁺ + 3OH⁻ ⇄ Fe(OH)₃ ↓ (solid precipitate)

Threfore, the concentration of Fe³⁺ ions in solution decreases.

See the rest of the answer in the image attached,since it cannot be loaded in the canvas.

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How do valence electrons relate to the chemical reactions of an element?

RoseWind [281]

Answer:

Explanation:

Valance electrons are loosely held electrons of an atom. They are involve in chemical reaction. Consider the example of metals such as group two metals. All these have two valance electrons. They needed six electrons to complete the octet or loses two valance electrons to get complete octet. Thus its easier to remove two electrons than getting six electrons. These metals remove two electrons and form cations.

Now consider the example of nonmetals such group sixteen. They needed two electrons to get complete octet or remove six electrons to get complete octet. Thus its easier for them to get two electrons and they form anion. When group two metals cation and group sixteen anions combine they form compound and chemical reaction occur.

Group two metals also combine with halogens. Two halogens atoms combine with one alkaline earth metal atom to cancel the charge and make compound neutral.

They react with oxygen and form oxide.

2Ba + O₂ → 2BaO

2Mg + O₂ → 2MgO

2Ca + O₂ → 2CaO

Oxygen carry -2 charge while Ca, Mg and Ba +2 and make the compound neutral because charges are equal in magnitude.

With sulfur,

Mg + S → MgS

Ca + S → CaS

Ba + S → BaS

Sulfer carry -2 charge while Ca, Mg and Ba +2 and make the compound neutral because charges are equal in magnitude.

3 0

4 years ago

What is the chemical formula for the compound magnesium perchlorate? Use the list of polyatomic ions and the periodic table to h

8_murik_8 [283]

The chemical formula for the compound magnesium perchlorate is Mg(ClO₄)₂

Magnesium perchlorate or Mg(ClO₄)₂ is an ionic compound.

Perchlorate here is an anion which is represented by ClO₄⁻. Perchlorate is a polyatiomic anion, where one Cl atom is bonded to four O atoms.

The magnesium cation is represented by Mg²⁺

So one Mg²⁺ cation combines with two ClO₄⁻ anion to form one molecule of Mg(ClO₄)₂

6 0

3 years ago

A 1.30M solution of BaCl2 has a density of 1.230 g/ml. a) What is the mole fraction of BaCl2 in this solution?

Elodia [21]

Answer: The mole fraction of barium chloride in the solution is 0.024

Explanation:

We are given:

Molarity of barium chloride solution = 1.30 M

This means that 1.30 moles of barium chloride is present in 1 L or 1000 mL of solution.

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.230 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

$1.230g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.230g/mL\times 1000mL)=1230g$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Moles of barium chloride = 1.30 moles

Molar mass of barium chloride = 208 g/mol

Putting values in equation 1, we get:

$1.30mol=\frac{\text{Mass of barium chloride}}{208g/mol}\\\\\text{Mass of barium chloride}=(1.30mol\times 208g/mol)=270.4g$

Mass of water = Mass of solution - Mass of barium chloride

Mass of water = 1230 - 270.4 = 959.6 g

Calculating the moles of water:

Given mass of water = 959.6 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{959.6g}{18g/mol}\\\\\text{Moles of water}=53.31mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For barium chloride:

$\chi_{\text{(barium chloride)}}=\frac{n_{\text{(barium chloride)}}}{n_{\text{(water)}}+n_{\text{(barium chloride)}}}$

$\chi_{\text{(barium chloride)}}=\frac{1.30}{1.30+53.31}\\\\\chi_{\text{(barium chloride)}}=0.024$

Hence, the mole fraction of barium chloride in the solution is 0.024

6 0

4 years ago

Using a spectrophotometer, and a cuvette with a path length of 1 cm you measure the absorbance (A275) of Guanosine to be 0.70. C

Anton [14]

Answer : The concentration of guanosine in your sample is, $8.33\times 10^{-5}M$

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

where,

A = absorbance of solution = 0.70

C = concentration of solution = ?

l = path length = 1.00 cm

$\epsilon$ = molar absorptivity coefficient guanosine = $8400M^{-1}cm^{-1}$

Now put all the given values in the above formula, we get:

$0.70=8400M^{-1}cm^{-1}\times C\times 1.00cm$

$C=8.33\times 10^{-5}M$

Thus, the concentration of guanosine in your sample is, $8.33\times 10^{-5}M$

5 0

3 years ago

Hydrogen gas reacts with oxygen to form water. 2H2(

denpristay [2]

The reaction is as follows:
2 H₂(g) + O₂(g) → 2 H₂O(g) . ΔH = - 483.5 kJ
Using the change in enthalpy and heat, calculate the moles as follows:
Moles of H₂ = - $\frac{amount of heat released}{ΔH}$ x 2 mol H₂
= - 216 kJ / (-483.5 kJ) x 2 mol H₂
= 0.893 mol H₂
Calculate the mass of H₂ using the moles and molar mass as follows:
0.893 mol H₂ x (2.02 g H₂ / 1 mol H₂) = 1.79 g H₂
Therefore, the mass of hydrogen gas is 1.79 g

7 0

4 years ago