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MA_775_DIABLO [31]
3 years ago
13

(01.04 MC)

Chemistry
1 answer:
jekas [21]3 years ago
3 0

Answer: Transformed to a different form of energy

Explanation:

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The average kinetic energy of translation of oxygen molecules in the gas is 5.05 × 10⁻²¹

The given data is

n = 2

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K.E = 3 / 2 KbT

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     = 3 / 2 Pv / nNa

K.E = 3 / 2 × 9 × 1.013 × 10⁵ × 20 × 10⁻³ / 2 × 6.022 × 10²³

K. E = 5.05 × 10⁻²¹ J

<h3>Average kinetic energy</h3>

The average kinetic energy (K) is equal to one half of the mass of each gas molecule times the RMS speed squared

Hence, the average kinetic energy is 5.05 × 10⁻²¹ J

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qualitative and quantitative

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There are three valence electrons in an atom of Aluminum (Al).
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The answer is B.
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4 years ago
What is the factor of 1024
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1
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