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VMariaS [17]
3 years ago
14

Find the distance between the points (1/2,4/3), (-2,1)

Mathematics
1 answer:
Gnoma [55]3 years ago
3 0

Answer:

Step-by-step explanation:

Redical of (229/36)

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bija089 [108]
K= 3. D=P. E=Q. F=R. G=S
5 0
3 years ago
Which number can be inserted in the box to make the equation below true?
Andrej [43]

Answer:

A. 5

Step-by-step explanation:

3 0
3 years ago
The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
Find the value of x. Round to<br> the nearest tenth.<br> 17°<br> 47<br> Х<br> X =[?]
elena-14-01-66 [18.8K]

Answer:

13.7 units

Step-by-step explanation:

Hi there!

The dotted lines and the hypotenuse of the green triangle create a new right triangle, with one of its acute angles measuring 17 degrees and its hypotenuse measuring 47 units.

Given this information and that we must solve for the side opposite the given angle, we can use the sine ratio:

sin\theta=\frac{opposite}{hypotenuse}

Plug in known information

sin17=\frac{x}{47}\\47*sin17=x\\13.7=x

Therefore, the value of x when rounded to the nearest tenth is 13.7 units.

I hope this helps!

4 0
3 years ago
Explain how you can tell if the product of a fraction and a whole number will be a whole number.
RSB [31]
Multiply the numerator with the whole number. If it is divisible by the denominator then it will be a whole number.
6 0
4 years ago
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