Answer: 694.4 in^2
Step-by-step explanation:
We have a cylinder with:
diameter = d = 10 inches
heigth = h = 16 inches.
The total surface of a cylinder is equal to:
S = h*2*pi*(d/2) + 2*pi*(d/2)^2
we can replace the numbers and get:
S = 16*2*3.14*(10/2) + 2*3.14*(10/2)^2 = 659.4 inches squared
Answer:
Question 7:
∠L = 124°
∠M = 124°
∠J = 118°
Question 8:
∠Q = 98°
∠T = 98°
∠R = 82°
Question 15:
m∠G = 110°
Question 16:
∠G = 60°
Question 17:
∠G = 80°
Question 18:
∠G = 70°
Step-by-step explanation:
The angles can be solving using Symmetry.
Question 7.
The sum of interior angles in an isosceles trapezoid is 360°, and because it is an isosceles trapezoid
∠K = ∠J = 118°
∠L = ∠M
∠K+∠J+∠L +∠M = 360°
236° + 2 ∠L = 360°
Therefore,
∠L = 124°
∠M = 124°
∠J = 118°
Question 8.
In a similar fashion,
∠Q+∠T+∠S +∠R = 360°
and
∠R = ∠S = 82°
∠Q = ∠T
∠Q+∠T + 164° = 360°
2∠Q + 164° = 360°
2∠Q = 196°
∠Q = ∠T =98°.
Therefore,
∠Q = 98°
∠T = 98°
∠R = 82°
Question 15.
The sum of interior angles of a kite is 360°.
∠E + ∠G + ∠H + ∠F = 360°
Because the kite is symmetrical
∠E = ∠G.
And since all the angles sum to 360°, we have
∠E +∠G + 100° +40° = 360°
2∠E = 140° = 360°
∠E = 110° = ∠G.
Therefore,
m∠G = 110°
Question 16.
The angles
∠E = ∠G,
and since all the interior angles sum to 360°,
∠E + ∠G + ∠F +∠H = 360°
∠E + ∠G + 150 + 90 = 360°
∠E + ∠G = 120 °
∠E = 60° = ∠G
therefore,
∠G = 60°
Question 17.
The shape is a kite; therefore,
∠H = ∠F = 110°
and
∠H + ∠F + ∠E +∠G = 360°
220° + 60° + ∠G = 360°,
therefore,
∠G = 80°
Question 18.
The shape is a kite; therefore,
∠F = ∠H = 90°
and
∠F +∠H + ∠E + ∠G = 360°
180° + 110° + ∠G = 360°
therefore,
∠G = 70°.
I forgot what they’re called but the angles opposite to each other are the same degree. It’s a theorem, just search up the name
The correct answer is 64 square units.
The area of the complete shape would be 100 square inches.
10 x 10 = 100
However, we have to remove the 4 corners. Each of the corners is 9 square inches. 3 x 3 = 9
100 - 4(9) = 64
Answer:
boys = 250
girls = 150
Step-by-step explanation:
5g = 3b eq. 1
g + b = 400 eq. 2
g = girls
b = boys
From the eq. 2
g = 400 - b
Replacing this last eq. on eq. 1:
5(400-b) = 3b
5*400 + 5*-b = 3b
2000 - 5b = 3b
2000 = 3b + 5b
2000 = 8b
2000/8 = b
250 = b
From eq. 2
g + 250 = 400
g = 400 - 250
g = 150
Check:
from eq. 1
5*150 = 3*250 = 750
