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4 years ago

If f3=0 and f1=12n, what does the magnitude of f⃗ 2 have to be for there to be rotational equilibrium?

Physics

1 answer:

QveST [7]4 years ago

4 0

<span>I found out F2 and its correct just need help in solving the other parts </span>
<span>F2 = 4.5 N </span>

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The magnitude of the electrostatic force between two identical ions that are separated by a distance of 5.0A is 3.7×10^-9N.a) wh

jeyben [28]

Explanation:

Given that,

Electrostatic force, $F=3.7\times 10^{-9}\ N$

Distance, $r=5\ A=5\times 10^{-10}\ m$

(a) $F=\dfrac{kq^2}{r^2}$ , q is the charge on the ion

$q=\sqrt{\dfrac{Fr^2}{k}}$

$q=\sqrt{\dfrac{3.7\times 10^{-9}\times (5\times 10^{-10})^2}{9\times 10^9}}$

$q=3.2\times 10^{-19}\ C$

(b) Let n is the number of electrons are missing from each ion. It can be calculated as :

$n=\dfrac{q}{e}$

$n=\dfrac{3.2\times 10^{-19}}{1.6\times 10^{-19}}$

n = 2

Hence, this is the required solution.

8 0

3 years ago

How much force must be applied for a 150.W motor to keep a package moving at 3.00m/s?

leva [86]

The force must be applied for motor to keep the package moving is 50 N.

<h3>What is force?</h3>

Force is the action of push or pull the object in order to make it move or stop.

Power is related to force and velocity as

P = F x v

150 W = F x 3 m/s

F =50 N

Thus, the force must be applied for motor to keep the package moving is 50 N.

Learn more about force.

brainly.com/question/13191643

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7 0

2 years ago

Which of these is most likely consequence of failing petroleum prices

melisa1 [442]

More sales of traditional, large cars are the most likely consequence of falling petroleum prices.

<h3>Explanation</h3>

Since the majority of conventional, large cars employ combustion engines, these engines need petroleum fuel to operate.

As a result, <em>Choice C—more sales of conventional, large cars</em>—is one of the effects of dropping oil prices that is most likely to occur.

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7 0

2 years ago

As you take your leisurely tour through the solar system, you come across a 1.45 kg rock that was ejected from a collision of as

nikklg [1K]

Answer:

$1.3310\times 10^8 m/s$ is the rock's speed.

Explanation:

Momentum is defined as motion possessed by the moving body's mass. Mathematically it a product of mas and velocity of the body.

$Momentum(P)=Mass(m)\times velocity(v)$

Given : Mass of rock = m = 1.45 kg

Velocity of the rock = v

Momentum of the rock = P = $1.93\times 10^8 kg m/s$

$1.93\times 10^8 kg m/s=1.45 kg\times v$

$v=\frac{1.93\times 10^8 kg m/s}{1.45 kg}=1.33\times 10^8 m/s$

$1.3310\times 10^8 m/s$ is the rock's speed.

6 0

3 years ago

To lift a load of 100 kg a distance of 1 m an effort of 25 kg must be applied over an inclined plane of length 4 m. What must be

Troyanec [42]

Using conservation of energy law:-
∑ work in = ∑ work out
and work= force* displacement
so when we wanted to move a 100kg a distance of 1m
we multiplied 100*1 = work out
so work in should be equal to 100*g Joules, where g is the acceleration due to gravity.
so workout = 100*g = 25*g *x (divide both sides by 25*g)
x=4m

by the same way:-
------------------------
work in = 100kg * 2m * g (m/ $s^2$ )= work out
so work out = 25*x*g = 200* g (divide both sides by 25*g)
x=8m

6 0

3 years ago

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