Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm fro
1 answer:
The ray diagram for the given object consists of 2 cm height of object, 4 cm object distance and 3 cm focal length.
<h3>Image formed by a diverging lens</h3>Diverging lens is called a concave lens. The working of the lens is dependent on the refraction of the light rays as they pass through the lens.
Image formed by a diverging lens is always virtual, erect and diminished; smaller than the object and is located on the same side of the lens as the object.
The ray diagram for the given object is presented in the image in the diagram.
- Object height = 2 cm
- Focal length = 3 cm
- Object distance = 4 cm
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<em>There is not enough data to solve the problem, but I'm assuming the initial height as h = 10 m for the question to have a valid answer and the student can have a reference to solve their own problem</em>
Answer:
(a)
(b)
Explanation:
<u>Change of Momentum</u>
The momentum of a given particle of mass m traveling at a speed v is given by
When this particle changes its speed to a value v', the new momentum is
The change of momentum is
Defining upward as the positive direction, we'll compute the change of momentum in two separate cases.
(a) The initial height of the superball of m=61.6 gr = 0.0616 Kg is set to h= 10 m. This information leads us to have the initial potential energy of the ball just after it's dropped to the floor:
This potential energy is transformed into kinetic energy just before the collision occurs, thus
Solving for v
This is the speed of the ball just before the collision with the floor. It's negative because it goes downward. Now we'll compute the speed it has after the collision. We'll use the new height and proceed similarly as above. The new height is
The potential energy reached by the ball at its rebound is
Thus the speed after the collision is
The change of momentum is
(b) If the putty sticks to the floor, then v'=0