The ray diagram for the given object consists of 2 cm height of object, 4 cm object distance and 3 cm focal length.
<h3>Image formed by a diverging lens</h3>Diverging lens is called a concave lens. The working of the lens is dependent on the refraction of the light rays as they pass through the lens.
Image formed by a diverging lens is always virtual, erect and diminished; smaller than the object and is located on the same side of the lens as the object.
The ray diagram for the given object is presented in the image in the diagram.
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Answer:
x' = 1.01 m
Explanation:
given,
mass suspended on the spring, m = 0.40 Kg
stretches to distance, x = 10 cm = 0. 1 m
now,
we know
m g = k x
where k is spring constant
0.4 x 9.8 = k x 0.1
k = 39.2 N/m
now, when second mass is attached to the spring work is equal to 20 J
work done by the spring is equal to
x'² = 1.0204
x' = 1.01 m
hence, the spring is stretched to 1.01 m from the second mass.