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3 years ago

What is the acceleration of the object in the graph?

Physics

1 answer:

viktelen [127]3 years ago

3 0

Answer:

-0.8 m/s²

Explanation:

Acceleration is the slope of a velocity vs. time graph.

a = Δv / Δt

a = (0 m/s − 12 m/s) / (15 s − 0 s)

a = -0.8 m/s²

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calculate the gravitational force in between two objects of mass 25 kg and 20 kg if distance between them is 5m

sladkih [1.3K]

Answer:

Gravitational force is 1.33 × 10^-9 N

Explanation:

$force = \frac{GMm}{ {r}^{2} }$

${ \sf{ = \frac{6.67 \times {10}^{ - 11} \times 25 \times 20 }{ {5}^{2} } }} \\ \\ = { \sf{1.33 \times {10}^{ - 9} \: newtons }}$

5 0

3 years ago

Distinguish between speed and velocity

Vanyuwa [196]

Velocity is a vector quantity, follows law of vector addition, has both direction and magnitude while speed is a scalar quantity , follows law of algebra and only has magnitude

4 0

3 years ago

2. A car is traveling with a velocity of 40 m/s and has a mass of 1,120 kg. Calculate the kinetic energy.

klasskru [66]

Answer:

896,000 J

Explanation:

m = 1,120 kg

v = 40 m/s

kinetic energy = mv^2/2 = 1,120 * 40^2/2= 896,000 J

7 0

3 years ago

If the voltage is 120 v, and the desired current is 5 a, what resistance must be in the circuit?

ch4aika [34]

Resistance = (voltage) / (current)

= 24 ohms.

7 0

3 years ago

Two football players collide head-on in midair while trying to catch a thrown football. The first player is 98.5 kg and has an i

romanna [79]

Answer:

$v_f=0.825m/s$

Explanation:

We must use conservation of linear momentum before and after the collision, $p_i=p_f$

Before the collision we have:

$p_i=p_1+p_2=m_1v_1+m_2v_2$

where these are the masses are initial velocities of both players.

After the collision we have:

$p_f=(m_1+m_2)v_f$

since they clong together, acting as one body.

This means we have:

$m_1v_1+m_2v_2=(m_1+m_2)v_f$

Or:

$v_f=\frac{m_1v_1+m_2v_2}{m_1+m_2}$

Which for our values is:

$v_f=\frac{(98.5kg)(6.05m/s)+(119kg)(-3.5m/s)}{(98.5kg)+(119kg)}=0.825m/s$

7 0

4 years ago