CaSO3 (s) → → → → CaO (s) + SO2 (g) What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temper

Question

Vlad [161]

3 years ago

12

CaSO3 (s) → → → → CaO (s) + SO2 (g) What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temper

ature of 12.5°C and a pressure of 1.10 atm?

Chemistry

1 answer:

Phoenix [80] · Answer 1 · 2022-08-18T05:52:07+03:00

Using the ideal gas law, the number of moles SO2 is equal to PV/RT, or pressure times volume divided by the gas constant and temperature. This is 14.5*1.1/((2.5+279.15)*.082), or 0.66 moles. Since one mole CaSO3 is consumed for every mole SO2 generated, 0.66 moles of CaSO3 are consumed. CaSO3 has a molar mass of 40+32+16*3=120 grams, so .66 moles of CaSO3 is equal to 80 grams, our final answer.