CaSO3 (s) → → → → CaO (s) + SO2 (g) What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temper
1 answer:
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Answer:
No
Explanation:
Let us examine this problem carefully:
Given compound is N₂O
Molecular mass = 88g
Now,
The empirical formula is the simplest formula of a compound.
The molecular formula is the true formula of the compound that shows that actual ratios of the atoms in a compound.
To find if they both have the same molecular and empirical formula, they must have the same molecular mass.
For N₂O;
Molecular mass = 2(14) + 16 = 44g/mole
But the true and given molecular formula of the compound is 88g/mole
This shows that the compound given is the empirical formula of the compound.
Molecular formula:
molecular mass of empirical formula x n = molecular mass of molecular formula
n = = 2
Molecular formula of compound = 2(N₂O) = N₄O₂
Therefore the empirical and molecular formulas are not the same
Answer: The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1
Explanation:
According to avogadro's law, equal volumes of all gases at same temperature and pressure have equal number of moles.
According to avogadro's law, 1 mole of every substance contains avogadro's number of particles.
Thus as oxygen and nitrogen are at same temperature and pressure and are in equal volume flasks , they have same number of moles and thus have same number of molecules.
The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1
As you have not provided the options, still we can figure out the answer by understanding the key difference between saturated and unsaturated hydrocarbons.
SATURATED HYDROCARBONS are those hydrocarbons which only consist of a carbon carbon single bonds. All the bonds are sigma there are no pi bonds at all. Examples are shown below.
While, UNSATURATED HYDROCARBONS are those hydrocarbons which may contain either a double bond or triple bonds or both of them between the carbon atoms as shown below.
