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3 years ago

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Calculate the pressure using the ideal gas law.

Chemistry

1 answer:

lubasha [3.4K]3 years ago

4 0

Answer:

Pressure, P = 67.57 atm

Explanation:

Given the following data;

Volume = 0.245 L
Number of moles = 0.467 moles
Temperature = 159°C
Ideal gas constant, R = 0.08206 L·atm/mol·K

Conversion:

We would convert the value of the temperature in Celsius to Kelvin.

T = 273 + °C

T = 273 + 159

T = 432 Kelvin

To find the pressure of the gas, we would use the ideal gas law;

PV = nRT

Where;

P is the pressure.
V is the volume.
n is the number of moles of substance.
R is the ideal gas constant.
T is the temperature.

Making P the subject of formula, we have;

$P = \frac {nRT}{V}$

Substituting into the formula, we have;

$P = \frac {0.467*0.08206*432}{0.245}$

$P = \frac {16.5551}{0.245}$

Pressure, P = 67.57 atm

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Answer:

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Explanation:

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3 years ago

there is a total of seventeen constitutional isomers for the molecular formula c5h13n. draw the skeletal formula of all three co

MAXImum [283]

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3 years ago

Could volume by displacement be used to determine the volume of a lump of rock salt? Explain would be nice

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Yes it could, but you'd have to set up the process very carefully.
I see two major challenges right away:

1). Displacement of water would not be a wise method, since rock salt
is soluble (dissolves) in water. So as soon as you start lowering it into
your graduated cylinder full of water, its volume would immediately start
to decrease. If you lowered it slowly enough, you might even measure
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So you would have to choose some other fluid besides water ... one in
which rock salt doesn't dissolve. I don't know right now what that could
be. You'd have to shop around and find one.

2). Whatever fluid you did choose, it would also have to be less dense
than rock salt. If it's more dense, then the rock salt just floats in it, and
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So the displacement method could perhaps be used, in principle, but
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3 years ago

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Answer:

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Explanation:

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Alexxandr [17]

Answer:

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