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Pani-rosa [81]
3 years ago
9

The electrons that are passed to nadp at the end of the electron transfer chain were obtained from

Chemistry
1 answer:
marshall27 [118]3 years ago
5 0
At the end of the electron transfer chain were obtained from chlorophyll 
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A white rooster mates with a black hen. The offspring is gray in color. What is this phenomenon called?
irina [24]

Answer:

A. co dominace

incomplete dominance is when both genes show, this would result in the chicken being a black and white color

Explanation:

4 0
3 years ago
How many carbon atoms would be in the compound named chlorobenzene
kondaur [170]

chlorobenzene
Carbon - 6
Hydrogen - 5
Chlorine - 1

that 1 chlorine replaces one of the hydrogens
thats why hydrogen number decreases by number of Cl atoms (that are substituting those H atoms)
7 0
3 years ago
Given a gas whose temperature is 418 K at a pressure of 56.0 kPa. What is the pressure of the gas if its Temperature changes to
Rainbow [258]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: \frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

P_{2} =\frac{T_{2} P_{1} }{T_{1} }

P_{2}=\frac{(337K)(0.55atm)}{418K}

P₂=0.44 atm

8 0
3 years ago
The atomic mass of gold is 197 g/mole, and the density of gold is 19.3 g/cm3. using this information along with the measured val
olganol [36]
The speed of sound is given by the formula
Speed of sound = square root (Young's Modulus/density)
Young's modulus for gold = 78 GPa which is 7.8 * 10^10 Pa
Speed of sound = (7.8 * 10^10 / 19.3 ) = sqrt (4.04 * 10^9 )
Speed of sound = 6.36 * 10^4 m/s <<<=== answer.
6 0
3 years ago
The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget?
Bezzdna [24]
Density = mass / volume
19.3 = 13 / m
m = 13 / 19.3
m = 0.67g

8 0
3 years ago
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