Answer:
the first one
Step-by-step explanation:
Answer:
Each student gets 2 1/3
Step-by-step explanation:
So you would divide 7 by 3, which you can't...so 6 divided by 3 is 2, and when you split the last one into thirds you can each have 1/3. Add the sections together, and each person gets 2 1/3
answer:
-4
Step-by-step explanation:
-3x+8= 20
-8 -8
-3x = 12
÷-3. = ÷-3
x = -4
10 students per gender:
Boys: <span>four Xs over five and one X over zero, two, three, four, ten, and twelve.
5, 5, 5, 5, 0, 2, 3, 4, 10, 12 </span>→ 0, 2, 3, 4, 5, 5, 5, 5, 10, 12<span>
mean: 5.1
range: 12
</span><span>Girls: three Xs above eight, two Xs above three and four, and one X above two, six and seven.
8, 8, 8, 3, 3, 4, 4, 2, 6, 7 </span>→ 2, 3, 3, 4, 4, 6, 7, 8, 8, 8
<span>mean: 5.3
range: 6
The boys have the higher range while the girls have the higher mean value.
</span><span>
</span>
f(x)= 3x³ - 18x +9
Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.
Identity I: (a + b)² = a² + 2ab + b²
Identity II: (a – b)² = a² – 2ab + b²
Identity III: a² – b²= (a + b)(a – b)
Identity IV: (x + a)(x + b) = x² + (a + b) x + ab
Identity V: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
Identity VI: (a + b)³ = a³ + b³ + 3ab (a + b)
Identity VII: (a – b)³ = a³ – b³ – 3ab (a – b)
Identity VIII: a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)
f(x) = (3x + 6) (x - 3)²
= ( 3x + 6) ( x - 3 )²
= ( 3x + 6)( x² - 6x + 9)
= 3x( x² - 6x + 9) + 6( x² - 6x + 9)
= 3x³ - 6x² + 18x + 6x² - 36x +9
= 3x³ - 18x +9
To learn more about algebraic expansions, refer to brainly.com/question/4344214
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