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Liono4ka [1.6K]
3 years ago
10

In order from left to right, what are the coefficients (front numbers) needed to

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
8 0

Answer:

2H2O2 → 2H2O + O2

Explanation:

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Calculate the quantity of electricity obtained from 2 moles of electrons​
Vinil7 [7]

The quantity of electricity : 2 Faraday = 193000 Coulomb

<h3>Further explanation</h3>

Given

2 moles of electrons

Required

The quantity of electricity

Solution

According to Faraday, the amount of current flowing in the electrolysis cell is closely related to the amount of substance that reacts

1 Faraday is the amount of electricity that is passed in the electrolysis cell to obtain 1 mole of electrons. 1 mole of electrons is equivalent to an electric charge of 96500 Coulombs.

The conversion / relationship can be stated as follows:

1 Faraday = 1 mole of electrons = 96500 Coulombs

1 faraday = coulomb / 96500

Can be formulated

Coulomb = Q = I. t so:

\large {\boxed {\bold {1 \: Faraday \: = \: \dfrac {i \: x \: t} {96500}}}}

so for 2 moles electrons :

= 2 x 96500 C

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6 0
3 years ago
The fire department needs information on friction losses occurring between a water main and an open fire hydrant. At maximum mai
lisov135 [29]

Explanation:

The given data is as follows.

      P_{1} = 85 psig,   P_{2} = P_{atm} = 15 psia

        Q = 1620 gpm,  d = 2.5 inch,     l = 8 ft = 2.4384 m

According to Darey-Weisbach equation,

                        h_{l} = \frac{4fl \nu^{2}}{2gD}  ......... (1)

Value of 'f' will be decided on the basis of Reynold number.

As, it is known that R_{l} = \frac{\rho \nu d}{\mu}

where,  \mu_{water} = 10^{-3} kg/ms

As it is known that 1 gpm = \frac{1}{3.67} m^{3}/hr

So,  1 m^{3}/hr = 3.67 gpm

Therefore,   Q = 1620 \times \frac{1}{3.67}

                        = 441.4168 m^{3}/hr

                         = 0.1226 m^{3}/s

In, 1 inch = 2.54 cm = 0.0254 m

Therefore, d = 2.5 \times 0.0254 = 0.0635 m

                V = \frac{Q}{\frac{\pi}{4}d^{2}}

                    = \frac{0.1226}{0.785 \times (0.0635)^{2}}

                    = 38.73 m/s

Hence, we will calculate Reynold number as follows.

             R_{l} = \frac{1000 \times 38.73 \times 0.0635}{10^{-3}}

                             = 2459355

As R_{l} > 2000 then, it means that flow is turbulent.

As, f = 0.079 R^{-0.25}_{l}

        = 0.001994

Putting all the values into equation (1) formula as follows.    

                          h_{l} = \frac{4fl \nu^{2}}{2gD}

                                     = \frac{4 \times 0.001994 \times 2.4384 \times (38.73)^{2}}{2 \times 9.81 \times 0.0635}

                                      = 1.04069 \times 10^{5} m

Thus, we can conclude that friction loss from the main to the discharge point is 1.04069 \times 10^{5} m.

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Which of the following is true for a nuclear reaction? (5 points)
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the identity of element remains same

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Genotypes are the genetic composition of an organism. Phenotype is the physical composition of an organism.

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