Suppose a blood sample tested above the range (6.0 mg/dL) of the standards used in the experiment. What modification will provid
e a more precise reading by data interpolation as opposed to extrapolation using the same standards?
1 answer:
Answer:
Using some dilutions of the mother solution
Explanation:
If there is a valid process by which the mother solution can be diluted with precision, the results must be in the range that are "normal".
If there are different dilutions that shows different results, but by graphing and extrapolating they show the same results as the mother solution, then the first measurement is correct.
This is also a method used to calibrate an instrument or to confirm the concentration of the mother solution.
check the graph.
Hope this info is useful.
You might be interested in
Answer:
The correct answer would be 2 in 4.
According to the question Xo and XO show codominance and express themselves completely when present in heterozygous condition. Cats bearing XoXO show patchwork of black and orange fur and are called tortoiseshell cats.
Xo codes for orange color fur and XO codes for black color fur. In addition, Y chromosome does not contain any gene associated with fur color.
Now, genotype of mother cat is XOXO (orange fur). So, the gametes formed would be XO only.
The genotype of father cat is XoY(black fur). So, the gametes would be Xo and Y.
The cross would lead to the formation of two male cats each having XOY as their genotype and two female cats each with XOXo as their genotype.
Hence, both the male cats would show orange fur and both the female cats would show patchwork of orange and black fur.
Therefore, we can conclude that 2 out of 4 would exhibit tortoiseshell coloring.
