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allsm [11]
3 years ago
11

Marybeth and Grant are pushing on a wagon, both pushing in opposite directions. Marybeth is pushing to the left with a force of

34 Newtons. Grant is pushing to the right with a force of 48 Newtons. What is the net force and which direction will the wagon move?
Physics
1 answer:
Vladimir [108]3 years ago
4 0

Answer:

14 N to the right

Explanation:

The net force is equal to the resultant of the forces acting on the wagon. In this case, we are considering two forces acting on the wagon:

- The force applied by Marybeth, to the left, of magnitude 34 N

- The force applied by Grant, to the right, of magnitude 48 N

Since the two forces are in opposite directions, in order to find the net force, we must choose a positive direction. Let's take "right" as positive direction, so the net force is:

F=+48 N-34 N=+14 N

And the positive sign means the net force is to the right. Due to this net force different from zero, the wagon will have an acceleration to the right, so if the wagon was at rest, it will start moving to the right.

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Provide one example of how Science drives Technology.
evablogger [386]

Answer:

Scientific knowledge is used to create new technologies. New technologies often allow scientists to explore nature in different ways and make new discoveries.

Explanation:

7 0
3 years ago
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X rays of wavelength 0.0169 nm are directed in the positive direction of an x axis onto a target containing loosely bound electr
mamaluj [8]

Answer:

a) 4.04*10^-12m

b) 0.0209nm

c) 0.253MeV

Explanation:

The formula for Compton's scattering is given by:

\Delta \lambda=\lambda_f-\lambda_i=\frac{h}{m_oc}(1-cos\theta)

where h is the Planck's constant, m is the mass of the electron and c is the speed of light.

a) by replacing in the formula you obtain the Compton shift:

\Delta \lambda=\frac{6.62*10^{-34}Js}{(9.1*10^{-31}kg)(3*10^8m/s)}(1-cos132\°)=4.04*10^{-12}m

b) The change in photon energy is given by:

\Delta E=E_f-E_i=h\frac{c}{\lambda_f}-h\frac{c}{\lambda_i}=hc(\frac{1}{\lambda_f}-\frac{1}{\lambda_i})\\\\\lambda_f=4.04*10^{-12}m +\lambda_i=4.04*10^{-12}m+(0.0169*10^{-9}m)=2.09*10^{-11}m=0.0209nm

c) The electron Compton wavelength is 2.43 × 10-12 m. Hence you can use the Broglie's relation to compute the momentum of the electron and then the kinetic energy.

P=\frac{h}{\lambda_e}=\frac{6.62*10^{-34}Js}{2.43*10^{-12}m}=2.72*10^{-22}kgm\\

E_e=\frac{p^2}{2m_e}=\frac{(2.72*10^{-22}kgm)^2}{2(9.1*10^{-31}kg)}=4.06*10^{-14}J\\\\1J=6.242*10^{18}eV\\\\E_e=4.06*10^{-14}(6.242*10^{18}eV)=0.253MeV

5 0
4 years ago
Sitting in a chairlift, Rebecca has a gravitational potential energy of 5,997.6
stira [4]

Answer:

B) 12 m

Explanation:

Gravitational potential energy is:

PE = mgh

Given PE = 5997.6 J, and m = 51 kg:

5997.6 J = (51 kg) (9.8 m/s²) h

h = 12 m

8 0
3 years ago
What is the force felt by the 64-kg occupant of the car? Express your answer to two significant figures and include the appropri
Yakvenalex [24]

Answer:

The force is -1.67\times10^{5}\ N

Explanation:

Given that,

Mass of car = 64 kg

Suppose,  a 1400-kg car that stops from 34 km/h on a distance of 1.7 cm.

We need to calculate the acceleration

Using formula of acceleration

v^2-u^2=2as

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value into the formula

0^2-(34\times\dfrac{5}{18})^2=2\times a\times 1.7\times10^{-2}

a=\dfrac{(34\times\dfrac{5}{18})^2}{2\times1.7\times10^{-2}}

a=-2623.45\ m/s²

We need to calculate the force

Using formula of force

F=ma

F=64\times(-2623.45)

F=-1.67\times10^{5}\ N

Negative sign shows the direction of the force is in the direction opposite to the initial velocity.

Hence, The force is -1.67\times10^{5}\ N

5 0
3 years ago
1.) A stone falls from rest from the top of a cliff.
KengaRu [80]

Answer:

Explanation:

ignore air resistance

Let t be the time of fall for the dropped stone.

½(9.8)t² = 43.12(t - 2.2) + ½(9.8)(t - 2.2)²

4.9t² = 43.12t - 94.864 + 4.9(t² - 4.4t + 4.84)

4.9t² = 43.12t - 94.864 + 4.9t² - 21.56t + 23.716

     0 = 21.56t - 71.148

t = 71.148/21.56 = 3.3 s

h = ½(9.8)3.3² = 53.361 = 53 m

or

h = 43.12(3.3 - 2.2) + ½(9.8)(3.3 - 2.2)² = 53.361 = 53 m

4 0
3 years ago
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