If I ask you to tell me the acceleration of gravity on Earth, you'll tell me a number. That acceleration of gravity is always that number, no matter WHEN you measure it. t doesn't change. So the graph of it is the number. The graph of a number is a horizontal line. Its equation is:
. Y = (the number) .
The correct choice is ' A ' .
Answer:
88m west and 50m north
Explanation:
1. Find the components of each vector in x and y:
(Please see the picture below)
- Vector 1:
Fx = 52m
Fy = 0m
- Vector 2:
Fx = 44m*cos34.6
Fy = 44m*sin34.6
- Vector 3:
Fx = 0m
Fy = 25m
2. Find the components of the final displacement acting in x and y:
For west direction:
Rx = 52m + 44m*cos34.6 + 0
Rx = 88m
For north direction:
Ry = 0 + 44m*sin34.6 + 25m
Ry = 50m
The work done on the gas is 37J as the piston compresses it from 1.00 L to 0.633 L.
<u>Explanation</u>:
<u>Given</u>:
Ideal gas temperature is 298 K
Atm=1.00
The piston compresses from 1.00 L to 0.633 L.
<u>To Find</u>:
The Work done on the gas
<u>Formula</u>:
W=P(V2 -V1)
where W is the work done on the gas,
P is the pressure of the chamber,
V2 is the second volume of the chamber,
V1 is the first volume of the chamber.
<u>Solution</u>:
W=P(V2 -V1)
Pressure P is 1 and V2 is 1 and V1 is 0.633
W=(1×10^5)(1-0.633)×10^-3
W=37J
Therefore the work done on the gas is 37J.
Answer:MOST COMMON METHOD IS USING A LUBRICANT -
A lubricant is a substance, usually organic, introduced to reduce friction between surfaces in ... medical examination. It is mainly used to reduce friction and to contribute to a better and efficient functioning of a mechanism. ... For lubricant base oil use, the vegetable derived materials are preferred
OTHER METHODS-
There are a number of ways to reduce friction:
Make the surfaces smoother. ...
Lubrication is another way to make a surface smoother.
Make the object more streamlined.
Reduce the forces acting on the surfaces.
Reduce the contact between the surfaces.
PLEASE DO MARK ME AS THE BRAINLIEST :)
Answer:
5.51 m
Explanation:
From the question,
The energy used to stretch the spring = the potential energy of the rock.
(1/2)ke² = mgh ................. Equation 1
Where k = spring constant, e = extension/compression, m = mass of the rock, g = acceleration due to gravity, h = height of the rock above the ground
make h the subject of the equation.
h = ke²/2mg ....................equation 2
Given: k = 5400 N/m, e = 1 m, m = 48 kg.
Constant: g = 9.8 m/s²
Substitute into equation 2
h = 5400(1²)/(2×48×9.8)
h = 5400/940.8
h = 5.51 m.
Hence the height of the rock = 5.51 m
