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Sveta_85 [38]
3 years ago
14

A stereo speaker produces a pure \"c\" tone, with a frequency of 262 hz. what is the period of the sound wave produced by the sp

Physics
1 answer:
jasenka [17]3 years ago
4 0

Answer:

3.82 ms

Explanation:

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

where f is the frequency.

In this problem, f = 262 Hz, so the period if this sound wave is

T=\frac{1}{262 Hz}=3.82\cdot 10^{-3} s=3.82ms

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nitially, scientists described atoms as the smallest particles of matter. However, smaller particles within atoms were discovere
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7 0
4 years ago
Photons of what minimum frequency are required to remove electrons from gold? note: the work function for gold is 4.8 ev.
kolbaska11 [484]
In the photoelectric effect, the energy given by the incoming photon is used partially to extract the electron from the metal (work function) and the rest is converted into kinetic energy of the electron:
hf= \phi + K
where
hf is the energy of the photon, with h being the Planck constant and f the frequency of the photon
\phi is the work function
K is the kinetic energy of the electron

When K=0, we have the minimum energy required to extract the electron from the metal, so the equation becomes
hf= \phi (1)

If we convert the work function of gold into Joules:
\phi=4.8 eV = 7.69 \cdot 10^{-19}J
We can re-arrange eq.(1) to find the minimum energy of the photon:
f= \frac{\phi}{h}= \frac{7.69 \cdot 10^{-19}J}{6.6 \cdot 10^{-34} Js} =1.17 \cdot 10^{15} Hz
5 0
4 years ago
What do you think causes the rising and sinking of molten rock in the mantle?
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Answer:

Heyyy hope this helps

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3 0
3 years ago
HELP + extra pts // Two 10-m high diving platforms are at opposing ends of a 30-m pool. How fast must two clowns run straight of
ZanzabumX [31]

Explanation:

The clowns need to leave the diving boards with enough horizontal velocity such that each travels 15 m (half the width of the pool) in the same time that they fall (vertically) the 10-m from the top of the diving board.

We'll assume no force acts on the clowns horizontally to slow them down while they are in flight. And we'll assume that only gravity acts on the clowns vertically.

We can treat the horizontal and vertical components separately. This will help simplify the problem.

Let's start with the vertical displacement. Let's say the clown is dropped from a height of 10-m. How long would it take them to fall that distance?

Using our equations of motion (with constant, linear acceleration), we can solve for this time. d = vt + \frac{1}{2} at^2

Where d is the distance travelled, v is the initial velocity, a is acceleration, and t is time.

If the clown is dropped, they have an initial velocity of 0 (zero). We assumed only gravity acts on the clown, so acceleration equals the gravitational acceleration on earth. a = 9.8m/s^2

The distance the clown travels is 10-m from the diving board to the surface of the water.

Let's solve. 10 = 0*t + \frac{1}{2} (9.8) t^2 \rightarrow 20/9.8 = t^2 \rightarrow t = \sqrt{20/9.8}

Now that we know time, we can calculate how fast the clown needs to be running when they leap from the diving board to cover a distance of 15-m (Remember, half the width of the pool.)

Using our equations of motion, we know that d = vt + 0.5at^2

We assumed no forces act horizontally on the clown, therefore a = 0. We just need to solve for v. Substituting in the time we just solved for, we get something like this. 15 = v \sqrt{20/9.8}

I'll leave it to you to solve this equation.

6 0
3 years ago
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