The buoyancy force on a floating object is: (select all that apply)
2 answers:
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This is an exercise in the general or combined gas law.
To start solving this exercise, we must obtain the following data:
<h3>Data:</h3>- V₁ = 4.5 l
- T₁ = 33 °C + 273 = 306 k
- P₁ = 6.54 atm
- T₂ = 94 °C + 273 = 367 k
- V₂ = 2.3 l
- P₂ = ¿?
We use the following formula:
- P₁V₁T₂ = P₂V₂T₁ ⇒ General Formula
Where
- P₁ = Initial pressure
- V₁ = Initial volume
- T₂ = Initial temperature
- P₂ = Final pressure
- V₂ = Final volume
- T₁ = Initial temperature
We clear the general formula for the final pressure.
We solve by substituting our data in the formula:
If I raise the temperature to 94°C and decrease the volume to 2.3 liters, the pressure of the gas will be 15,346 atm.