Answer:
Explanation:
Which of the Following Correctly Balances this Equation? _H2+_Cl2 --> _HCl
1 answer:
You might be interested in
Answer:
I cannot give you all the answer but I can help you to solve those.
Explanation:
The first question:
How many grams are there in 7.5× molecules of
?
So we need to find the molecular mass first, use your periodic table,
And then we can find out 2+32+16×4=98 g/mol
Then, we need to find how many moles, by using Avogadro's constant:
Avogadro's constant: 1 mole = 6.02×
∴=1.25 mol(2d.p.)
Lastly, find the grams using the formula
m=Mn
m=1.25*98
m=122.5g
-------------------------------------------------------------------------------------------------------------
In conclusion, use those formula to help you:
(which M = molecular mass(atomic mass) m=mass of the substance and n = moles)
Avogadro's constant:
LiAlH₄ is used as strong reducing agent. The hydride produced acts as a nucleophile and attacks the electrophillic carbon of carbonyl group. In given example two reactions are observed.
Reaction 1:
In first step LiAlH₄ when treated with Ester produces corresponding Aldehyde and alcohol.
Reaction 2:
This aldehyde produced further reacts with LiAlH₄ to give a reduced product (Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
Reaction 1:
In first step LiAlH₄ when treated with Ester produces corresponding Aldehyde and alcohol.
Reaction 2:
This aldehyde produced further reacts with LiAlH₄ to give a reduced product (Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
Answer:
M = 0.011
Half reactions for reduction and oxidation:
oxidation:
HC12H6Cl2O2N + NH+ +2e- = HC12H8Cl2O2N
reduction:
C6H8O6 = C6H6O6 + 2H+ + 2e-
Explanation:
Molarity of the ascorbic acid solution:
Ascorbic acid molar mass = 173.12 g/mol
Then you have to find the mols:
mol = 2g/176,12 =0.011 mol Ascorbic acid.
Use the molarity equation:
Molarity (M) = 0.011 mol / 1 L = 0.011 M
Reactions for the reduction of DCPIP by ascorbic acid:
These reactions have to be balanced by the oxide reduction method.
Because it involves the transfer of electrons from ascorbic acid to the DCPIP.
Remember: when is happens a reduction, also happens oxidation.
To see the reactions watch the images attached.
The first one has the calculus for the molarity of the ascorbic acid solution.
The second one has the reactions for the reduction and oxidation of the compounds.
