Ask question

Ask question

All categories

DanielleElmas [232]

3 years ago

6

If the value of the electric field in an electromagnetic wave were doubled then

1 answer:

Norma-Jean [14]3 years ago

4 0

Answer:

Electromagnetic wave are waves formed as a result of the oscillatory activities involving the electric and the magnetic field.

However in an Electromagnetic wave, the electric field and magnetic field carry equal amounts of energy and the magnitude of the electric field is directly proportional to the magnitude of the magnetic field. This direct proportionality gives rise to the speed of light being the constant between the two fields.

When the electric field is doubled then an equal action is to be set for the magnetic field so it doesn’t deviate from its main functions and characteristics.

You might be interested in

Which of the following is true about producers?

Nina [5.8K]

the answer is d they are essential to all ecosystems

4 0

3 years ago

2. A stone is thrown vertically upward with a speed of 22m/s.

Eduardwww [97]

Answer:

Explanation:

Energy E is conserved:

$E=\frac{1}{2}mv^2+mgh$

If v₀ = 22m/s, h₀=0m and h₁=25m:

$E=\frac{1}{2}mv_0^2=\frac{1}{2}mv_1^2+mgh_1$

Solving for v₁:

$v_1=\sqrt{v_0^2-2gh_1}$

There is no real solution, because the stone never reaches 25m.

7 0

3 years ago

If you break a piece of glass, the shape of the glass changes, but the properties in the

lutik1710 [3]

Answer:

It would be a physical change because you aren't changing to chemical properties of the glass, just the shape.

6 0

3 years ago

How is light energy converted to chemical energy in photosynthesis?

jasenka [17]

Oooooooooooooooooooooooooooooooooooo

7 0

3 years ago

A diffraction grating produces a first-order bright fringe that is 0.18 m away from the central bright fringe on a flat screen.

Georgia [21]

Answer:

The wavelength of the light is 562.5 nm

Solution:

As per the question:

Order, n = 1

Slit separation, d = $2.5\times 10^{- 6}\ m$

Distance from the bright fringe, y = 0.18 m

Distance between the screen and the grating, D = 0.8 m

Now,

We know from the eqn for diffraction:

$n\lambda = dsin\theta$

n = 1

$\lambda = dsin\theta$ (1)

Also,

For very small angle, $\theta$ :

$sin\theta$ ≈ $tan\theta = \frac{y}{D} = \frac{0.18}{0.8} = 0.225$

Using the above value in eqn (1):

$\lambda = 2.5\times 10^{- 6}\times 0.225 = 5.625\times 10^{- 7}\ m = 562.5\ nm$

3 0

3 years ago