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4 years ago

A branch falls from a tree. how fast is the branch moving after 0.28 seconds

Physics

2 answers:

victus00 [196]4 years ago

6 0

The answer should be 2.75 m/s. Hope this helps.

kogti [31]4 years ago

4 0

2.74m/s

Since the branch is falling under gravity we can use one of the equations of motion:

v=u+at

This becomes:

v=0+gt

∴v=9.8×0.28=2.74m/s

This assumes no air resistance.

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A ball is kicked and flies from point P to Q following a parabolic path in which the highest point reached is T. The acceleratio

Semenov [28]

After the foot leaves the ball, the acceleration is always downward and is equal to g at all points

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3 years ago

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a person takes a trip, driving with a constant speed of 89.5 km/h except for a 22.0 min rest stop. if the person’s average speed

fredd [130]

TheThe distance they have covered for trip is 219Km.

<h3>What do you mean by uniformly accelereted motion?</h3>

When an object is traveling in a straight line with an increase in velocity at equal intervals of time.

The total time for the trip is

T→ t1+ 22 min = t1+ 0.367 h ,where t1 is the time spent traveling at

V1= 89.5 km/ h .

the distance traveled is ∆x = V1t1=Vavg T

after applying value and calculating it we get

t1= 2.44h for a total time of

t total we get 2.81 h .

∆x =V1T1 = VavgTtotal

∆x = 77×2.81= 219 Km

to learn more about Uniform accelereted motion click here brainly.com/question/12920060

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3 0

2 years ago

Machines

Ainat [17]

Explanation:

Hey there!!

Here, Given is,

Efficiency = 75%

VR = no. of pulleys = 5

Now,

$effeciency = (\frac{ma}{vr} ) \times 100\%$

$75\% = \frac{ma}{5} \times 100\%$

100% ma = 75%×5

$ma = \frac{75\% \times5}{100\%}$

$ma = \frac{375\%}{100\%}$

Therefore, MA is 3.75.

Hope it helps...

3 0

3 years ago

Read 2 more answers

A 1000kg car has a speed of 32m/s. If it takes 7s to stop the car, what is the impulse and the average force acting in the car

Alexus [3.1K]

1) Impulse: -32,000 kg m/s

The impulse acting on the car is equal to the change in momentum of the car:

$I= \Delta p = m (v-u)$

where in this problem we have

m = 1000 kg is the mass of the car

v = 0 m/s is the final velocity of the car

u = 32 m/s is the initial velocity of the car

Substituting values into the equation, we find

$I=(1000 kg)(0-32 m/s)=-32,000 kg m/s$

2) -4751 N

The impulse exerted on the car is also equal to the product between the average force, F, and the duration of the collision, t:

$I=Ft$

where in this situation we know

$I=-32,000 kg m/s$ is the impulse

t = 7 s is the duration of the collision

Solving the formula for F, we find the average force:

$F=\frac{I}{t}=\frac{-32,000 kg m/s}{7 s}=-4,571 N$

and the negative sign means that the force is in the opposite direction to the motion of the car.

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3 years ago

A joule is used to measure a. power. b. energy. c. torque. d. pressure.

KATRIN_1 [288]

The Joule is the SI unit of energy.

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3 years ago