Answer:
1/3
Explanation:
We can solve the problem by using the lens equation:
where
f is the focal length
p is the distance of the object from the lens
q is the distance of the image from the lens
Here we have a divering lens, so the focal length must be taken as negative (-f). Moreover, we know that the object is placed at a distance of twice the focal length, so
So we can find q from the equation:
Now we can find the magnification of the image, given by:
Answer:100 meters per min
Explanation:
Answer: 6.12metres
Explanation:
The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ
Recall that Wavespeed (V) = Frequency F x wavelength λ
V = F λ
In this case,
Wavespeed of sound = 1530 m/s
Frequency of sound = 2.50 x 10^2 Hz
Wavelength = ? (let the unknown value be Z)
Apply V = F λ
1530 m/s = 2.50 x 10^2 Hz x Z
Z = (1530 m/s / 2.50 x 10^2 Hz)
Z = (1530 m/s / 250Hz)
Z = 6.12m
Thus, the wavelength of sound in sea water is 6.12m
A sphere??????????
i think thats the answer
Answer:
Explanation:
a ) The angle required = angle of repose = θ
Tanθ = .81
θ = 39⁰
b ) when angle of incline θ = 44
Net force on the block = mg sinθ - μ mg cosθ where μ is coefficient of kinetic friction
acceleration = gsinθ - μ g cosθ
= 9.8 ( sin44 - μ cos44 )
= 9.8 ( .695 - .69 x .72 )
= 9.8 ( .695 - .497 )
= 1.94 m /s²
