The Kissing Number Problem: It is a sphere packing problem that includes spheres. Group spheres are packed in space or region has kissing numbers. The kissing numbers are the number of spheres touched by a sphere.

The Unknotting Problem: It the algorithmic recognition of the unknot that can be achieved from a knot. It defined the algorithm that can be used between the unknot and knot representation of a closely looped rope.

The Large Cardinal Project: it says that infinite sets come in different sizes and they are represented with Hebrew letter aleph. Also, these sets are named based on their sizes. Naming starts from small-0 and further, prefixed aleph before them. eg: aleph-zero.

7 0

3 years ago

Assignment: Wed : Finding Unit Rates (7.RP.1, 7. RP.2, 7.RP.2a

spayn [35]

Answer:

Step-by-step explanation:

6 0

3 years ago

Pat needs to determine the height of a tree before cutting it down to be sure that it will not fall on a nearby fence. The angle

dem82 [27]

Answer:

229.23 feet.

Step-by-step explanation:

The pictorial representation of the problem is attached herewith.

Our goal is to determine the height, h of the tree in the right triangle given.

In Triangle BOH

$Tan 60^0=\dfrac{h}{x}\\h=xTan 60^0$

Similarly, In Triangle BOL

$Tan 50^0=\dfrac{h}{x+60}\\h=(x+60)Tan 50^0$

Equating the Value of h

$xTan 60^0=(x+60)Tan 50^0\\xTan 60^0=xTan 50^0+60Tan 50^0\\xTan 60^0-xTan 50^0=60Tan 50^0\\x(Tan 60^0-Tan 50^0)=60Tan 50^0\\x=\dfrac{60Tan 50^0}{Tan 60^0-Tan 50^0} ft$

Since we have found the value of x, we can now determine the height, h of the tree.

$h=\left(\dfrac{60Tan 50^0}{Tan 60^0-Tan 50^0}\right)\cdotTan 60^0\\h=229.23 feet$

The height of the tree is 229.23 feet.

5 0

3 years ago