Answer:
y(-4) = 5
y'(-4) = -7
Step-by-step explanation:
Hi!
Since the tangent line T and the curve y must coincide at x=-4
y(-4) = T(-4) = 5
On the other hand, the derivative of the curve evaluated at -4 y'(x=-4) must be the slope of the tangent line. Which inspecting the tangent line T(x) is -7
That is:
y'(-4) = -7
Answer:
x=5
Step-by-step explanation:
im so bad at explaining things but i hope this helped
-9x^3-72x^2+36=3x^3+x^2-3x+8 Add 9x^3 to both sides.
-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8 Add 72x^2 to both sides
36 = 12x^3 + 73x^2 - 3x + 8 Subtract 36 from both sides.
0 = 12x^3 + 73x^2 - 3x - 28
It does factor, but it is not very nice.
(x + 6.06)(x - 6.09)(x + 0.632)
If there is any kind of error please report it in a note below.
<u>Given </u><u>:</u><u>-</u>
- The slope of the line through points (3,y) and (4,10) is 7 .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
As we know that the slope of the line is difference of ordinate divided by the difference of absicca as ,
m = y -10 / 3 - 4
7 (-1) = y -10
-7 = y -10
y = 10 -7
y = 3
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>3.</u>
