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aksik [14]
3 years ago
14

Question 7 please????

Mathematics
2 answers:
Ahat [919]3 years ago
7 0

Answer:

I think it would be 17 because if you subtract 47 by 13 it will give you 34 and if you divide it by 2 it will give you 17.

Make me brainliest

Andreyy893 years ago
7 0

Answer:

The length of longer piece is 30 inches.

Step-by-step explanation:

Firstly, you have to make an expression in terms of x where x represents the length of the <u>s</u><u>h</u><u>o</u><u>r</u><u>t</u><u>e</u><u>r</u><u> </u><u>p</u><u>i</u><u>e</u><u>c</u><u>e</u> . Given that the total length is 47 inches and the longer piece is 13 inches longer that the shorter one. Using this information, you can form an expression :

Shorter piece =>

x inches

Longer piece =>

(13 + x) inches

Total length =>

x + 13 + x = 47

2x + 13 = 47

now, you can solve to find the value of x by substracting 13 to both sides then divide it by 2:

2x + 13 - 13 = 47 - 13

2x = 34

2x ÷ 2 = 34 ÷ 2

x = 17 inches

We have found the shorter piece. The question wants to find the longer piece so you have to substitute the value of x into the expression of longer piece :

Let x be 17 inches,

13 + x = 13 + 17

= 30 inches

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If y=(x^2-4)^5(3x+4)^4
alexira [117]

Answer:

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

Step-by-step explanation:

y=(x^2-4)^5(3x+4)^4

y'=[\frac{d}{dx}(x^2-4)^5](3x+4)^4+(x^2-4)^5[\frac{d}{dx}(3x+4)^4]

y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)

y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

5 0
2 years ago
Find the area of the shaded region .
klasskru [66]
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Area of a rectangle=length x width.

Area of the greater rectangle=(8x-1)(6x)
area of the inner rectangle=(5x+3)(2x)

Area of the shaded region=(8x-1)(6x)-(5x+3)(2x)
=48x²-6x-(10x²+6x)
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Answer: the area of the shaded region would be: 38x²-12x
8 0
3 years ago
Suppose point P(4,-9) is transmitted according to rule (x,y)→(x+3,y-2),what are the coordinates of P
malfutka [58]

Answer:

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6 0
3 years ago
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

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Step-by-step explanation:

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Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
hakim wrote an equation to represent the number of meters he would run for each kilometer, k, in a long distance race.W hat is t
ASHA 777 [7]
K=500 because of the kilometer
5 0
3 years ago
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