Using the quadratic equation we get:

Factoring out 2 we get

Factoring out the imaginary number:

So b.
Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.





We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
If we are to connect the root of the tree to a person to the top of the tree, we form two right triangles. If we let x and and 200 - x be the distance of Harris and Annabelle from the tree, respectively and h be the height, we form the trigonometric functions,
tan 30° = h/x
tan 35° = h/(200 - x)
The values of h and x in the equations are 63.28 ft and 109.62 ft, respectively. Thus, the answer to this item is approximately 63.28 ft.
Divide until you get one moth alone then multiply then simplify if you don't know how to simplify please pm me.