The paragraph to show the comparision between two classes semester grades on the basis of the terms
- extremes
- quartiles
- medians
- ranges
is given below:
<h3>What is Box and Whisker plots?</h3>
A box and whisker plot is defined as a graphical method of displaying variation in a set of data.
From the first figure, write all the values where dark point is drawn
53, 62, 80, 86, 89
- The lower extreme is the smallest value, which is 53.
The upper extreme is the highest value, which is 89.
- The median will be the middle of data , which is 80
- The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.
The upper quartile is 86 and the lower quartile is 62.
= Highest - Lowest
=89-53
=36
From the second figure, write all the values where dark point is drawn
56, 62, 74, 89, 96
- The lower extreme is the smallest value, which is 56.
The upper extreme is the highest value, which is 96.
- The median will be the middle of data , which is 74.
- The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.
The upper quartile is 89 and the lower quartile is 62.
= Highest - Lowest
=96-62
=34
From the above discussion,
- The First class have less upper extreme value than the second class.
- The First class have less lower extreme value than the second class.
- The First class have greater median than the second class.
- The First class have less upper quartile than the second class.
- The First and second class have equal lower quartile.
- The First class have greater range than the second class.
The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.
learn more about box and whisper plot here:
brainly.com/question/11859288
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Answer:
503
Step-by-step explanation:
For an arithmetic sequence, the n-th term is found by
To find 
(the common difference) we can simply subtract one of the terms by the last, for example:
The common difference must be the same throughout the entire sequence, so we can do it once more just to be sure:
We also have to know that 
stands for the first term of the sequence, which in this case is 311.
Now that we know this, let's find the 32nd term
Good luck!
Answer:
Let's suppose that each person works at an hourly rate R.
Then if 4 people working 8 hours per day, a total of 15 days to complete the task, we can write this as:
4*R*(15*8 hours) = 1 task.
Whit this we can find the value of R.
R = 1 task/(4*15*8 h) = (1/480) task/hour.
a) Now suppose that we have 5 workers, and each one of them works 6 hours per day for a total of D days to complete the task, then we have the equation:
5*( (1/480) task/hour)*(D*6 hours) = 1 task.
We only need to isolate D, that is the number of days that will take the 5 workers to complete the task:
D = (1 task)/(5*6h*1/480 task/hour) = (1 task)/(30/480 taks) = 480/30 = 16
D = 16
Then the 5 workers working 6 hours per day, need 16 days to complete the job.
b) The assumption is that all workers work at the same rate R. If this was not the case (and each one worked at a different rate) we couldn't find the rate at which each worker completes the task (because we had not enough information), and then we would be incapable of completing the question.
8• (5+x) < 56
That is the equation
