Answer:
2.5
Step-by-step explanation:
Conversion a mixed number 2 1/
2
to a improper fraction: 2 1/2 = 2 1/
2
= 2 · 2 + 1/
2
= 4 + 1/
2
= 5/
2
To find new numerator:
a) Multiply the whole number 2 by the denominator 2. Whole number 2 equally 2 * 2/
2
= 4/
2
b) Add the answer from previous step 4 to the numerator 1. New numerator is 4 + 1 = 5
c) Write a previous answer (new numerator 5) over the denominator 2.
Two and one half is five halfs
Answer:
g(x)=(x-2)^2
Step-by-step explanation:
the equation of of the graph of g(x) is:
g(x)=(x-2)^2, since the following transformation has been done to it:
right one unit
since the equation in vertex form is g(x)=a(x-h)^2+k, it is moved two units to the right and not to the left
since g(x) has the same shape, it had not been compressed or stretched by any means, meaning that a is 1
Given the question: Arrange the reasons for the proof in the correct order.
Prove: If the diameter of a circle is 6 meters and the formula for
diameter is d = 2r, then the radius of the circle is 3 meters.
A. If r ≠ 3 m, then d ≠ 6 m. Since the contrapositive is true, the
original statement must also be true. Therefore, if the diameter of a
circle is 6 meters, then the radius is 3 meters.
B. Multiplication of real numbers shows that d = 2(2 m) = 4 m.
C. Substitute r = 2 m into d = 2r.
D. Assume that r ≠ 3 m. For example, the radius equals another length,
such as r = 2 m.
To prove that i<span>f the diameter of a circle is 6 meters and the formula for diameter is d = 2r, then the radius of the circle is 3 meters by contradiction, we assume that the radius in not equal to 3 meters, for </span>example, the radius equals another length,
such as r = 2 m.
Next, we substitute the value: r = 2m nto the original equation that says that d = 2r, i.e. d = 2(2m) = 4m which is not true and contradicts the original statement that the diameter of the circle is 6m.
Therefore, the arrangement of the proof is as follows:
D. Assume that r ≠ 3 m. For example, the radius equals another length,
such as r = 2 m.
C. Substitute r = 2 m into d = 2r.
B. Multiplication of real numbers shows that d = 2(2 m) = 4 m.
A. If r ≠ 3 m, then d ≠ 6 m. Since the contrapositive is true, the
original statement must also be true. Therefore, if the diameter of a
circle is 6 meters, then the radius is 3 meters.
D C B A.
