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3 years ago

Due to the tilt of the Earth's axis,

1 answer:

3 0

6 months with no sunrise and the other 6 without a sunset, at some places on Earth, are the result of the orientation of Earth's axis.

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One student made the incomplete diagram shown below to represent the relationship between igneous rocks, sediments, sedimentary

Kryger [21]

Answer: Option (C)

Explanation: Rock cycle plays an important role in the alteration of rocks from one form to another.

Igneous rocks when undergoes high temperature and pressure condition, it transforms into a metamorphic rock.
Sedimentary rocks are formed from the sedimentation and consolidation of sediments
Igneous rocks are formed due to the crystallization of magma.

Hence the correct answer is option (C)

3 0

4 years ago

A man weighing 980 n on earth

Alla [95]

Answer:

91.84kg

Explanation:

6 0

3 years ago

Read 2 more answers

Calculate the average Power in kilowatts required to pull a car up a ramp in the amount of work is 250 KJ over a period of 45 se

kherson [118]

For this case we have that by definition, the average power is given by:

$P = \frac {W} {t}$

Where:

W: It is the work done

t: It's time

According to the data we have to:

$W = 250 \ KJ = 250,000 \ J\\t = 45 \ s$

So:

$P = \frac {250,000} {45}\\P = 5555.55 \ watts = 5.56 \ kw$

Answer:

$5.56 \ kw$

5 0

4 years ago

The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50∘C is 2000 m/s. Note that 1.0 mol of diatomic hydrogen at

denis-greek [22]

Answer:

A) d. (1/4)(2000m/s) = 500 m/s

B) c. 4000 J

C) f. None of the above (2149.24 m/s)

Explanation:

The translational kinetic energy of a gas molecule is given as:

K.E = (3/2)KT

where,

K = Boltzman's Constant = 1.38 x 1^-23 J/K

T = Absolute Temperature

but,

K.E = (1/2) mv²

where,

v = root mean square velocity

m = mass of one mole of a gas

Comparing both equations:

(3/2)KT = (1/2) mv²

v = √(3KT)/m _____ eqn (1)

FOR HYDROGEN:

v = √(3KT)/m = 2000 m/s _____ eqn (2)

FOR OXYGEN:

velocity of oxygen = √(3KT)/(mass of oxygen)

Here,

mass of 1 mole of oxygen = 16 m

velocity of oxygen = √(3KT)/(16 m)

velocity of oxygen = (1/4) √(3KT)/m

using eqn (2)

velocity of oxygen = (1/4)(2000 m/s) = 500 m/s

K.E = (3/2)KT

Since, the temperature is constant for both gases and K is also a constant. Therefore, the K.E of both the gases will remain same.

K.E of Oxygen = K.E of Hydrogen

K.E of Oxygen = 4000 J

using eqn (2)

At, T = 50°C = 323 k

v = √(3KT)/m = 2000 m/s

m = 3(1.38^-23 J/k)(323 k)/(2000 m/s)²

m = 3.343 x 10^-27 kg

So, now for this value of m and T = 100°C = 373 k

v = √(3)(1.38^-23 J/k)(373 k)/(3.343 x 10^-27 kg)

v = 2149.24 m/s

8 0

4 years ago

What is the displacement of the object?

sveta [45]

Answer:

Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

6 0

3 years ago