Answer:
Explanation:
Impulse of reaction force of floor = change in momentum
Velocity of impact = √ 2gh₁
= √ 2 x 9.8 x 1.5 = 5.4 m /s.
velocity of rebound = √2gh₂
= √ 2x 9.8 x 1
= 4.427 m / s.
Initial momentum = .050 x 5.4 = .27 kg m/s
Final momentum = .05 x 4.427 = .22 kg.m/s
change in momentum = .27 - .22 = .05 kg m/s
Impulse = .05 kg m /s
Impulse = force x time
force = impulse / time
.05 / .015 = 3.33 N.
kinetic energy = 1/2 m v²
Initial kinetic energy = 1/2 x .05 x 5.4²
= 0.729 J
Final Kinetic Energy =1/2 x .05 x 4.427²
= 0.489 J
Change in Kinetic energy =0 .24 J
Lost kinetic energy is due to conversion of energy into sound light etc.
Answer:
The fraction of the ball's kinetic energy stored in the spring is 3.6KJoules
Explanation:
Given
Mass of ball =0.5kg
Velocity of ball =120m/s
The kinetic energy stored by the ball is expressed as
K.E=1/2(m*v²)
Substituting our data into the expression we have
K. E=(0.5*120²)/2
K. E=7200/2
K.E=3,600 JOULE
K.E=3.6KiloJoules
The watt<span> (symbol: W) is a unit of power i hope this helps you</span>
