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Zina [86]
3 years ago
7

The decomposition of H2O2 is first order in H2O2 and the rate constant for this reaction is 1.63 x 10-4 s-1. How long will it ta

ke for [H2O2] to fall from 0.95 M to 0.33 M?
Chemistry
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

It will take 6486.92 minutes  for [H2O2] to fall from 0.95 M to 0.33 M

Explanation:

The order of reaction is defined as the sum of the powers of the concentration terms in the equation. Order of a reaction is given by the number of atoms or molecule whose concentration change during the reaction and determine the rate of reaction.

In first order reaction;

In \dfrac{a}{a_o-x}= k_1 t

where;

a = concentration at time t

a_o = initial concentration

and k = constant.

In (\dfrac{0.33}{0.95})= -1.63 \times 10^{-4} \times t

-1.05736933 = -1.63 \times 10^{-4} \times t

t = \dfrac{-1.05736933}{  -1.63 \times 10^{-4} }

t = 6486.92 minutes

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