Question

If sin Θ = 5/6 , what are the values of cos Θ and tan Θ?

Answer 1

Sin t (theta) = 5/6
cos t = √( 1 - (5/6)²) = √(1-25/36 ) = √(11/36) = √11 / 6
tan t = sin t / cos t = 5 / 6 : √11 / 6 = 5 / 6 · 6 / √ 11 = 5 / √11 

Answer 2

sin = opp/hyp, so the lacking side, is the adjacent side. 5²+b²=6² b=√(6²-5²) = √11≈3.32 Cos = adj /hyp = √11 / 6 (simplifying to) 1.66/3 Tan = opp / adj =5 / √11