The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M
Using ICE table:-
Acetic acid + Isopentyl alcohol ------> Isopentyl acetate + water
I 8M 4M 0 0
C 8-x 4-x +x +x
E 8-x 4-x +x +x
Equilibrium constant (Keq) = 4.2
On using the equilibrium expression -
Keq = [Product] / [Reactant]
Keq = x^2 / (8-x) (4-x )
4.2 = x^2 / 32 - 8x - 4x + x^2
x = 3.4
Concentration of acetic acid = 8-x = 8-3.4 = 4.6M
Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M
Concentration of isopentyl acetate = x = 3.4M
Concentration of water = x = 3.4M
Learn more about equilibrium expression
brainly.com/question/14751091
#SPJ4
Answer:
2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an excess (unlimited) supply of Pb(CH₃COO)₂
Explanation:
The balanced reaction is:
Pb(CH₃COO)₂ + H₂S → 2 CH₃COOH + PbS
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) they react and produce:
- Pb(CH₃COO)₂: 1 mole
- H₂S: 1 mole
- CH₃COOH: 2 moles
- PbS: 1 mole
In this case, to know how many grams of H₂S are needed to produce 18.00 g of PbS, it is first necessary to know the molar mass of the compounds H₂S and PbS and then to know how much it reacts by stoichiometry. Being:
- H: 1 g/mole
- S: 32 g/mole
- Pb: 207 g/mole
The molar mass of the compounds are:
- H₂S: 2* 1 g/mole + 32 g/mole= 34 g/mole
- PbS: 207 g/mole + 32 g/mole= 239 g/mole
So, by stoichiometry they react and are produced:
- H₂S: 1 mole* 34 g/mole= 34 g
- PbS: 1 mole* 239 g/mole= 239 g
Then the following rule of three can be applied: if 239 grams of PbS are produced by stoichiometry from 34 grams of H₂S, 18 grams of PbS from how much mass of H₂S is produced?

mass of H₂S= 2.56 grams
<u><em>2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an excess (unlimited) supply of Pb(CH₃COO)₂</em></u>
Answer :electrostatic repulsion.
EXPLANATION
Valence shell electron pair repulsion theory, or VSEPR theory, is a model used in chemistry to predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms
Answer : The correct option is B (clay, slit, sand).
Explanation :
Soil particles are of three types : Sand, Slit and clay. Most of the soils particles are made up of a combination of sand, slit and clay.
Particle size range of the sand = 2.00 -0.05 mm
Particle size range of the slit = 0.05 -0.002 mm
Particle size range of the sand = less than 0.002 mm
Sand is the largest soil particle, clay is the smallest soil particle and slit particle is present in between the sand & clay particle.
Therefore, the order from smaller to larger sediment particles is
Clay > Slit > Sand