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nignag [31]
3 years ago
5

Lithium diisopropylamide [(CH3)2CH]2NLi, referred to as LDA, enjoys many uses as a strong base in synthetic organic chemistry. I

t is customarily prepared by the reaction of diisopropylamine [(CH3)2CH]2NH with butyllithium. Draw the products of the reactions in the appropriate boxes and select the acid, base, conjugate acid, and conjugate base. Be sure to answer all parts.

Chemistry
1 answer:
meriva3 years ago
5 0

Answer:

Lithium diisopropylamide [(CH3)2CH]2NLi.

Explanation:

Lithium diisopropylamide (commonly abbreviated LDA) is a chemical compound with the molecular formula [(CH3)2CH]2NLi. It is used as a strong base and has been widely accepted due to its good solubility in non-polar organic solvents and non-nucleophilic nature. It is a colorless solid, but is usually generated and observed only in solution. It was first prepared by Hamell and Levine in 1950 along with several other hindered lithium diorganylamides to effect the deprotonation of esters at the α position without attack of the carbonyl group.

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C3H8+5O2 --> 3CO2 + 4H2O
Tresset [83]

Answer:

3, 4 ,1

Explanation:

6 0
3 years ago
In your reaction you started with a solution that was approximately 8 M acetic acid and 4 M isopentyl alcohol. Use the equilibri
V125BC [204]

The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M

Using ICE table:-

      Acetic acid  +  Isopentyl alcohol   ------>    Isopentyl acetate +  water

I         8M                   4M                                           0                           0

C        8-x                   4-x                                          +x                          +x                      

E        8-x                   4-x                                          +x                          +x

Equilibrium constant (Keq) = 4.2

On using the equilibrium expression -

Keq = [Product] / [Reactant]

Keq = x^2 / (8-x) (4-x )

4.2  =  x^2 / 32 - 8x - 4x + x^2

    x =  3.4

Concentration of acetic acid  = 8-x = 8-3.4 = 4.6M

Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M

Concentration of isopentyl acetate = x = 3.4M

Concentration of water = x = 3.4M

Learn more about equilibrium expression

brainly.com/question/14751091

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4 0
2 years ago
How many grams of H2S is needed to produce 18.00g of PbS if the H2S is reacted with an
goldenfox [79]

Answer:

2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an  excess (unlimited) supply of Pb(CH₃COO)₂

Explanation:

The balanced reaction is:

Pb(CH₃COO)₂ + H₂S → 2 CH₃COOH + PbS

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) they react and produce:

  • Pb(CH₃COO)₂: 1 mole
  • H₂S: 1 mole
  • CH₃COOH: 2 moles
  • PbS: 1 mole

In this case,  to know how many grams of H₂S are needed to produce 18.00 g of PbS, it is first necessary to know the molar mass of the compounds H₂S and PbS and then to know how much it reacts by stoichiometry. Being:

  • H: 1 g/mole
  • S: 32 g/mole
  • Pb: 207 g/mole

The molar mass of the compounds are:

  • H₂S: 2* 1 g/mole + 32 g/mole= 34 g/mole
  • PbS: 207 g/mole + 32 g/mole= 239 g/mole

So, by stoichiometry they react and are produced:

  • H₂S: 1 mole* 34 g/mole= 34 g
  • PbS: 1 mole* 239 g/mole=   239 g

Then the following rule of three can be applied: if 239 grams of PbS are produced by stoichiometry from 34 grams of H₂S, 18 grams of PbS from how much mass of H₂S is produced?

mass of H_{2} S=\frac{18 grams of PbS*34 grams of H_{2}S }{239 grams of PbS}

mass of H₂S= 2.56 grams

<u><em>2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an  excess (unlimited) supply of Pb(CH₃COO)₂</em></u>

8 0
4 years ago
BRAINLIEST FOR FREE AND FREE 20 POINTS FOR HELPING ME!!!
natita [175]

Answer :electrostatic repulsion.

EXPLANATION

Valence shell electron pair repulsion theory, or VSEPR theory, is a model used in chemistry to predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms

8 0
3 years ago
help plz Which list is in order from smaller to larger sediment particles? A. sand, silt, clay B. clay, silt, sand C. silt, sand
MariettaO [177]

Answer : The correct option is B (clay, slit, sand).

Explanation :

Soil particles are of three types : Sand, Slit and clay. Most of the soils particles are made up of a combination of sand, slit and clay.

Particle size range of the sand = 2.00 -0.05 mm

Particle size range of the slit = 0.05 -0.002 mm

Particle size range of the sand = less than 0.002 mm

Sand is the largest soil particle, clay is the smallest soil particle and slit particle is present in between the sand & clay particle.

Therefore, the order from smaller to larger sediment particles is

Clay > Slit > Sand

5 0
4 years ago
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