CH4 - no lone pairs
HCl - 3 lone pairs
H2O - 2 lone pairs
NH3 - 1 lone pair (answer)
Answer:
the volume of a set of keys is 6.75ml
One point that is not true is an electron orbital has the same amount of energy in all orbital.
hope this helps!
Oxidation is a process in which electrons are lost from the substance. Since electrons are lost, oxidation state increases.
In the above reaction, we can see that oxidation state increases for Mn from 0 to +2. That mean Mn is undergoing oxidation.
![Mn(s)----->Mn^{2+}(aq) +2e^{-}](https://tex.z-dn.net/?f=%20Mn%28s%29-----%3EMn%5E%7B2%2B%7D%28aq%29%20%2B2e%5E%7B-%7D%20%20)
We have ![E_{ox} = 0.34V](https://tex.z-dn.net/?f=%20E_%7Box%7D%20%3D%200.34V%20)
The oxidation state decreases for Cu, that means Cu undergoes reduction.
![Cu^{2+}(aq) + 2e^{-} ------> Cu(s)](https://tex.z-dn.net/?f=%20Cu%5E%7B2%2B%7D%28aq%29%20%2B%202e%5E%7B-%7D%20------%3E%20Cu%28s%29%20)
![E_{red} =1.18V](https://tex.z-dn.net/?f=%20E_%7Bred%7D%20%3D1.18V%20)
The formula to calculate cell potential is
![E_{cell} = E_{ox} + E_{red}](https://tex.z-dn.net/?f=%20E_%7Bcell%7D%20%3D%20E_%7Box%7D%20%2B%20E_%7Bred%7D%20%20)
Let us plug in the given Eox and Ered values.
![E_{cell} = 0.34V+1.18V](https://tex.z-dn.net/?f=%20E_%7Bcell%7D%20%3D%200.34V%2B1.18V%20)
![E_{cell} = 1.52V](https://tex.z-dn.net/?f=%20E_%7Bcell%7D%20%3D%201.52V%20)
The overall cell potential is +1.52V
The amount of heat energy added to silver to heat it from 25°C to 100°C is :
8737.5 J
<u>Given data: </u>
mass of silver ( m ) = 500 g
T1 = 25°C
T2 = 100°C
s ( specific heat of silver ) = 0.233 J/g.c
<h3 /><h3>Determine the amount of heat required </h3>
Applying the formula below for heat ( Q )
Q = ms * ΔT
= 500 * 0.233 * ( 100 - 25 )
= 8737.5 J
Hence we can conclude that the The amount of heat energy added to silver to heat it from 25°C to 100°C is : 8737.5 J.
Learn more about heat energy : brainly.com/question/13439286