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katen-ka-za [31]
3 years ago
5

How many orbitals are available in a “d” orbital configuration?

Chemistry
1 answer:
ratelena [41]3 years ago
8 0

Answer:

e.)5

Explanation:

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2. Determine the molarity of the NaOH solution in each trial. a. Trial 1 Molarity: b. Trial 2 Molarity: 3. Calculate the average
butalik [34]

Answer:

This question is incomplete

Explanation:

This question is incomplete but...

1) You can calculate the molarity of the NaOH for each trial by following the steps below.

The formula for Molarity (M) is

M = number of moles (n) ÷ volume (V)

where the unit of volume must be in Litres or dm³

The unit of molarity is mol/dm³ or mol/L or molar conc (M)

The final answer must have the unit of molarity

If the number of moles is not provided, look out for the mass of NaOH used and then calculate your number of moles (n) as

n = mass of NaOH used ÷ molar mass of NaOH

Where the atomic mass of sodium (Na) is 23, oxygen (O) is 16 and hydrogen (H) is 1. Hence, molar mass for NaOH is 23 + 16 + 1 = 40 g/mol

n = mass of NaOH used ÷ 40

2) Average Molarity will be (Trial 1 Molarity +Trial 2 Molarity) ÷ 2

Answer must be in mol/dm³ or mol/L or M

3) Label the volumentric flask containing the NaOH solution with the answer gotten from (2) above

3 0
3 years ago
Which type of reaction occurs when 50mL quantities of 1 M Ba(OH)2 (aq) and H2SO4 (aq) are combined
iragen [17]
Double replacement.

Ba(OH)2 + H2SO4 ====> 2H2O + BaSO4
5 0
3 years ago
What has a higher density Ice cubes or ice spheres pls pls pls help​
Verizon [17]
The answer is Ice spheres
6 0
3 years ago
-, or stirring, of the solute in the solvent
Hoochie [10]
Agitation, or stirring of the solute in the solvent increases the solubility of the solution
7 0
3 years ago
Write the condensed formula from left to right, starting with (CH3)x where x is a number.
pochemuha

Complete question:

Write the condensed formula from left to right, starting with (CH3)x where x is a number.

See attached image for the structure formula of the compound

Answer:

(CH₃)₂CHC(CH₃)₃ named as 2,2,3-Trimethylbutane

Explanation:

If we number the longest chain of the carbon starting from the left, we will observe that there are four carbons in the straight chain as shown in the image.

Starting from first carbon from the left of the carbon chain, at carbon number number 2, there two alkyl group, that is two methyl (CH3 is two). Also at carbon number 3, there are three alkyl group, that is three methyl (CH3 is three).

The condensed formula will be written as;

(CH₃)₂CHC(CH₃)₃

This compound is named as 2,2,3-Trimethylbutane, an isomer of Heptane

3 0
3 years ago
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