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2 years ago

A 500 ml aqueous solution of na3po4 was prepared using 82g of the solute. what is the molarity

Chemistry

1 answer:

liraira [26]2 years ago

7 0

Answer:

1 M

Explanation:

The molarity of a solution, M, is a measure of the concentration of that solution and it refers to the number of moles of solute (mol) per liter (L) of solution. The molarity (M) can be calculated using the formula:

M = number of moles (n) /volume (V)

In this question, a 500 ml aqueous solution of Na3PO4 was prepared using 82g of the solute.

Molar mass of Na3PO4 = 23(3) + 15 + 16(4)

= 69 + 31 + 64

= 164g/mol

Mole = mass/molar mass

mole = 82/164

mole = 0.5 mol

Volume in Litres (L) = 500 ml ÷ 1000 = 0.500L

Therefore, Molarity (M) = 0.5/0.500

Molarity = 1 M or 1 mol/L

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<h3>Further explanation</h3>

Given

50g nitrous oxide

50g oxygen

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3 years ago

A 500 ml aqueous solution of na3po4 was prepared using 82g of the solute. what is the molarity​

A 500 ml aqueous solution of na3po4 was prepared using 82g of the solute. what is the molarity