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maksim [4K]
3 years ago
14

How many moles is 2.80 x 10^24 atoms of silicon

Chemistry
1 answer:
neonofarm [45]3 years ago
3 0
The answer that i found is 4.650
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Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
What is the percent composition of each of the elements in Al(OH) 3 ?
stellarik [79]

Answer:

<em>Answer Below</em>

Explanation:

Percent composition by element

<u>Element </u>       <u>Symbol</u>  <u>Mass Percent</u>

Aluminium <u>Al</u>          34.590%

Hydrogen <u>H</u>          3.877%

Oxygen         <u>O</u>          61.533%

3 0
3 years ago
Read 2 more answers
In Period 2, as the elements are considered from left to
Elza [17]

Answer:

it will option B ,hope it helps

5 0
3 years ago
Can y'all help me with number 4
astraxan [27]
I think the answer is A but i'm not sure
6 0
3 years ago
Read 2 more answers
HELP ASAP WILL MARK BRAINLIEST: How many grams of aluminum can be extracted from 5000g of alumina
Lesechka [4]

The grams of aluminium extracted from 5000g of alumina is 2647 grams

<h3>Chemical formula of alumina:</h3>
  • Al₂O₃

Let's calculate the molecular mass of Al₂O₃

Al₂O₃ = 27 × 2 + 16 × 3 = 54 + 48 = 102 g/mol

Therefore,

102 g of Al₂O₃ = 54 g of aluminium  

5000g of Al₂O₃  = ?

mass of aluminium produced = 5000 × 54 / 102

mass of aluminium produced = 270000 / 102

mass of aluminium produced  = 2647.05882353

mass of aluminium produced  = 2647 grams

learn more on mass here: brainly.com/question/14627327

4 0
2 years ago
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