Answer:
b. HCOOH/ NaHCOO.
Explanation:
A buffer system may be formed in one of two forms:
- A weak acid with its conjugate base.
- A weak base with its conjugate acid.
Chose the pairs below that you could use to make a buffered solution.
a. HCI/NaOH. NO. HCl is a strong acid and NaOH is a strong base.
b. HCOOH/ NaHCOO. YES. HCOOH is a weak acid and HCOO⁻ (coming from NaHCOO) is its conjugate base.
c. HNO₂/H₂SO₃. NO. Both are acids and they are unrelated to each other.
d. NaNO₃/ HNO₃. NO. HNO₃ is a strong acid.
Answer:
the answer is I'm pretty that it's
Explanation:
Ur Wellcome
Answer:
Ca(OH)₂ + H₂SO₄ → CaSO₄ + H₂O
Explanation:
Chemical equation:
Ca(OH)₂ + H₂SO₄ → CaSO₄ + H₂O
Balanced chemical equation:
Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O
The given reaction is double displacement reaction in which anion and cation of both reactant exchanged with each other. Calcium hydroxide react with sulfuric acid and form calcium sulfate and water.
Double replacement:
It is the reaction in which two compound exchange their ions and form new compounds.
AB + CD → AD +CB
Answer:
Yes
Explanation:
Yes, A substance can be a lewis acid without being a Bronsted-Lowery acid because there are some substances which cannot donate protons(Bronsted-Lowery acid) but can accept a pair of electron.
<u><em>For Example:</em></u>
Let us take the example of BF₃
BF₃ contains no proton so it is not a Bronsted Lowery Acid
However, BF₃ has an incomplete octet with 6 electrons. It needs an electron pair to complete its octet. It accepts a pair of electron to become a Lewis Acid
