Answer:
4.1 m
Explanation:
Given :
Mass of the block = m = 2 kg.
Initial velocity = 
= 8 m/s
Angle of the incline = α = 30°
Coefficient of friction = μ = 0.35
Distance moved up the incline is calculated using the work energy theorem.
Work done by the net force = change in kinetic energy of the object.
Net work = work done by friction + work done by the gravity component.
(- mg sin 30 - μ mg cos 30 ) d = 
m cancels out when divided on both sides with m.
- [(9.8 sin 30 - ( 0.35 × 9.8 × cos 30) ] d = 1/2 ( 0² - 8² )
⇒ -7.87 d = -32
⇒ Distance traveled up the incline = d = 4.0658 m = 4.1 m
The modifications that are implemented after Tacoma bridge disaster are added trusses and openings below road decks to decrease oscillations.
<h3>Why Tacoma Bridge disaster occurred?</h3>
While marching, the natural frequency of the vibrations of marching soldiers matched up with the resonant frequency of the bridge. This resulted in the collapsing of the bridge in seconds.
Because of the disaster of the Tacoma Narrows Bridge, the bridge was strengthened by adding trusses as well as openings below road decks so as to decrease vibrations caused by running vehicles on the bridge.
Thus, the modifications that are implemented after Tacoma bridge disaster are added trusses and openings below road decks to decrease oscillations
Learn more about Tacoma Bridge disaster.
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Resonance occurs<span> when the amplitude of an object's oscillations are increased by the matching vibrations of another object.
Source: </span>Resonance: Definition & Transmission of Waves
The tension in the supporting cable when the cab originally moves downward is 18422.4 N
What is tension?
Tension is described as the pulling force by the means of a three-dimensional object.
Tension might also be described as the action-reaction pair of forces acting at each end of said elements.
Here,
m =combined mass = 1600 kg
s = Displacement of the elevator = 42 m
g = Acceleration due to gravity = 9.81 m/s²
u = Initial velocity = 12 m/s
v = Final velocity = 0
According to the equation of motion:
0 - 12^2 = 2*a*42
a = - 144 / 84
a = - 1.714 m/s^2
Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:
T-mg = ma
T = m(g-a)
T = 1600 ( 9.8-(-1.74))
T=18422.4 N
Hence,
The tension in the supporting cable when the cab, originally moving downward is 18422.4 N
Learn more about tension here:
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