Kari drew two parallel lines PQ and RS intersected by a transversal KL, as shown below:

How many significant figures will there be in the answer to the following

serious [3.7K]

can you show me a picture then maybe i can help you

4 0

3 years ago

A rectangular cooler made of MycoFoam is 13 inches wide, 7 inches tall, and 7 inches long. what is its surface area?

yarga [219]

To find area u have to multiply the sides so it should be 7x7 or 13x7 it shouldnt be 13x7x7

6 0

3 years ago

WITH PICTURE!!3. What is the value of x in the regular polygon below? (3 points)

monitta

Answer: FIRST OPTION.

Step-by-step explanation:

Regular polygons are those polygons whose sides are equal in length and whose angles are all equal.

By definition each interior angle of a Regular polygon,is:

$\frac{180 ( n -2 )}{n}$ (In degrees)

Where "n" is the number of sides of the polygon.

Observe the Regular polygon given in the exercise.

Since it has 6 sides, you can conclude that it is an Hexagon. Then:

$n=6$

Substituting into $\frac{180 ( n -2 )}{n}$ and evaluating, you get:

$\frac{180 ( 6 -2 )}{6}=120\°$

Knowing this, you can write the following equation:

$3x=120$

Finally, you must solve for "x" in order to find its value. This is:

$x=\frac{120}{3}\\\\x=40$

8 0

4 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

4 years ago

Бу2 + 13y – 8 how to factorize this?

Anettt [7]

Answer:

We have 6y² + 13y - 8. We can rewrite this as 6x² + 16x - 3x - 8. Grouping terms we get 2x(3x + 8) - (3x + 8) and since both terms have the common factor of (3x + 8) the answer is (3x + 8)(2x - 1).

7 0

4 years ago