Answer:
WAN or wide area network
Explanation:
The Internet is the most basic example of a WAN. It is connecting all computers together around the world.
Answer:
Answer choice 4
Explanation:
If Josh sends an e-mail to his... co-<em>worker</em>.... wouldn't that be... <em>work</em>place communication?
Answer: E. Never
geometric average return can NEVER exceed the arithmetic average return for a given set of returns
Explanation:
The arithmetic average return is always higher than the other average return measure called the geometric average return. The arithmetic return ignores the compounding effect and order of returns and it is misleading when the investment returns are volatile.
Arithmetic returns are the everyday calculation of the average. You take the series of returns (in this case, annual figures), add them up, and then divide the total by the number of returns in the series. Geometric returns (also called compound returns) involve slightly more complicated maths.
Don’t stress. You’re no failure if you believe in yourself. Have some faith. Don’t give up and live your life to the fullest. Take care and stay safe!! :)
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}