Software that help user of all levels can go be several names:
Web Authoring Software
Visual Web Authoring Software
A WYSIWYG editor
Website design and development application.
It really depends on the text book or your instructor as to what term they use.
As for me?
I use an IDE (Integrate Development Environment), but that is not for all user levels...but if you know what you are doing they cannot be beat!
Answer is: looking through many lines of code for errors that cause bugs
Explanation:
A software engineer with a detail oriented personality has the patience and aptitude for looking through many lines of code for errors that cause bugs
Because software writes many lines of code for developing different application so he has to go through through many lines of code for errors that causes a bug or errors.
I hope you got the idea and answer thanks.
Answer:
Im sorry if im wrong but i took a class for coding a long time ago but i think it is 6 :)
Answer:
a) # include <iostream>
# include <conio.h>
# include <stdio.h>
# include <string.h>
using namespace::std;
bool IsPalindrome(const string& str)
{
if (str.empty())
return false;
int i = 0; // first characters
int j = str.length() - 1; // last character
while (i < j)
{
if (str[i] != str[j])
{
return false;
}
i++;
j--;
}
return true;
}
int main()
{
string str;
cout<<"Enter the string";
getline(cin, str);
bool a= IsPalindrome(str);
if(a)
{
cout<<"Is in palindrome";
}
else
{
cout<<"Is not in palindrome";
}
}
b) Modified version of function with full program to discard uppercase or lowercase is as below:
# include <iostream>
# include <conio.h>
# include <stdio.h>
# include <string.h>
using namespace::std;
bool IsPalindrome(const string& str)
{
if (str.empty())
return false;
int i = 0; // first characters
int j = str.length() - 1; // last character
while (i < j)
{
char a= tolower(str[i]);
char b= tolower(str[j]);
if (a != b)
{
return false;
}
i++;
j--;
}
return true;
}
int main()
{
string str;
cout<<"Enter the string";
getline(cin, str);
bool a= IsPalindrome(str);
if(a)
{
cout<<"Is in palindrome";
}
else
{
cout<<"Is not in palindrome";
}
}
Explanation:
Please check the answer section.
