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inna [77]
2 years ago
12

In variogram modeling with multiple variables and anisotropy, if all the variograms cannot be modeled well, it is critical to mo

del the cross variograms well while the other models can be sacrificed somewhat?
Mathematics
1 answer:
siniylev [52]2 years ago
6 0

Answer:

The statement is false.

Step-by-step explanation:

If the modeling is with multiple variables it is necessary for all the variables to be modeled well such that the criticality of the model is dependent on all the variograms. It is not dependent on the cross variograms only.

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Can someone help me with all this?? i really dont get it ​
olga nikolaevna [1]

Answer:

A=78

B=102

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Step-by-step explanation:

A= a and 102 are on a straight line so they add up to 180. 180-102=78. The same goes for C

B= the vertical angle for 102, or the same thing with a and c, just flipped around

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2 years ago
Arie ran an equal number of miles each day for 12 days. He ran 60 miles in total.
Nezavi [6.7K]

Answer:

5 miles/day

Step-by-step explanation:

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3 years ago
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3 years ago
-1(x+5)=3[x+(2x-1)]<br> solved and justified each step
madreJ [45]

Answer:

<h2>x = -0.2</h2>

Step-by-step explanation:

-1(x+5)=3[x+2x-1)]\\\\\text{for}\ -1(x+5):\ \text{distribtutive property}\\\text{for}\ [x+(2x-1)]:\ \text{associative property}\\\\(-1)(x)+(-1)(5)=3[(x+2x)-1]\\-x-5=3(3x-1)\\\\\text{for}\ 3(3x-1):\ \text{distributive property}\\\\-x-5=(3)(3x)+(3)(-1)\\-x-5=9x-3\\\\\text{for the equation}:\ \text{addition property of equality}\\\\-x-5=9x-3\qquad\text{add 5 to both sides}\\-x-5+5=9x-3+5\\-x=9x+2\\\\\text{for the equation:}\ \text{subtraction property of equality}\\\\-x=9x+2\qquad\text{subtract}\ 9x\ \text{from both sides}

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\text{Distributive property:}\ a(b+c)=ab+ac\\\text{Associative property:}\ (a+b)+c=a+(b+c)

6 0
2 years ago
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