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Lyrx [107]
3 years ago
6

How can writing phrases as algebraic expressions help me solve problems

Mathematics
1 answer:
Iteru [2.4K]3 years ago
7 0
It helps u cuz u need to know how 2 isolate the variable or something in math terms 
Hope i helped!!!=-O =-O :-P :-P :-P 
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Is 1/28 = 16 1/2? I’m just using extra word because it making me type more but please answer ASAP
masya89 [10]

Answer:

NO IT IS NOT

Step-by-step explanation:

16 1/2 = 16.5 1/28 = 0.0357

NOT THE SAME!!!!!

Please mark brainiest if this is helpful! :D

8 0
3 years ago
Read 2 more answers
If the right angle triangle LMN.<br>L=30°, MN = 4cm and diagonal LM.<br>Find the LM and LN.​
Gnoma [55]
LM is 6.9 to 1dm and LM is 8
7 0
3 years ago
Please help me
morpeh [17]

Answer:

No, because the cone has a smaller volume than the ice cream

Step-by-step explanation:

V=4

3πr3=4

3·π·33≈113.09734

Volume of scoop: 113.1 cm^2

V=πr2h

3=π·2.52·10

3≈65.44985

Volume of cone: 65.45 cm^2

65.45 < 113.1

6 0
3 years ago
Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:
Nataly_w [17]
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>

remember that 
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
1/cos(theta)=sec(theta)-------------> is ok

the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
6 0
3 years ago
Read 2 more answers
Resolve (5x+4) /( (x-4)( x+2))
vazorg [7]

Answer:

Step-by-step explanation:

Hello!

(5x+4) /( (x-4)( x+2))

(5x+4)/ (x² +2x -4x -8)=

(5x+4) /( x²-2x -8)

7 0
3 years ago
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