Answer:
Mass = 1.42 g
Explanation:
Given data:
Amount of heat absorbed = 4.56 j
Initial temperature = 29°C
Final temperature = 36°C
Mass of iron metal = ?
Specific heat capacity of iron = 0.46 j/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 36°C - 29°C
ΔT = 7°C
Q = m.c. ΔT
m = Q / c. ΔT
m = 4.56 j / 0.46 j/g°C . 7°C
m = 4.56 j /3.22 j/g
m = 1.42 g
Kc at 298K is Kc = 1 × 10^84.
Calculation:
The relation between Kp and Kc is
Kp = KcRT
The value of Kp is known
We can calculate the value of Kc with this
R = 8.3145 J mol^−1 K^−1 .
T = 298K
Kp = KcRT
2.5×10⁸⁷ = Kc × 8.3145 × 298
2.5×10⁸⁷ = Kc × 2477.572
Kc = 1 × 10^84
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Answer:
When magma cools, crystals form because the solution is super-saturated with respect to some minerals. If the magma cools quickly, the crystals do not have much time to form, so they are very small. If the magma cools slowly, then the crystals have enough time to grow and become large.
Explanation:
Answer:
5.1622 mol This is the answer for your questions
Answer:
reee, here is your answer.
Explanation: CH3OH(l) + 3O2(g) rightarrow CO2(g) + 3H2O(g) CH3OH(l) + O2(g) rightarrow CO2(g) + 2H20(g) CH3OH(l) + 2O2(g) rightarrow 2CO2(g) + 4H20(g) 2CH3OH(l) + 3O2(g) rightarrow 2CO2(g) + 4H20(g) Correct Calculate Delta H degree rxn at 25 degree C.
