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3 years ago

Calculate the average atomic mass element X

Chemistry

1 answer:

Leto [7]3 years ago

5 0

Answer:

39.02 amu

Explanation:

The average atomic mass of an element can be calculated as follows :

$X=\dfrac{9.67\times 38+78.68\times 39+11.34\times 40+0.31\times 41}{100}\\\\X=\dfrac{3902.29}{100}\\\\X=39.02\ amu$

So, the atomic mass of the element X is 39.02 amu.

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What is the name of the giant bubble of charged gas that surrounds the sun?

solniwko [45]

The correct answer is A. The gin bubble of charged gas around the sun is called the heliosphere. Basically, the heliosphere is a sphere of helium. This is a region where the solar wind is said to have an influence.

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3 years ago

what is the correct conversion factor by which to multiply to convert moles of nitrogen to moles of ammonium nitrate (NH4NO3)

Ostrovityanka [42]

Answer:

0.5

Explanation:

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the conversation factor is 0.5

6 0

3 years ago

Read 2 more answers

A compound is composed of only C, H, and O. The combustion of a 0.519-g sample of the compound yields 1.24 g of CO 2 and 0.255 g

vredina [299]

Answer:

$\large\boxed{\large\boxed{C_3H_3O}}$

Explanation:

1. Calculate the mass of C in 1.24 g of CO₂

$1.24gCO_2\times \dfrac{12.011gC}{44.01gCO_2}=0.3384gC$

2. Calculate the mass of H in 0.255g of H₂O

$0.255gH_2O\times \dfrac{2.016gH}{18.015gH_2O}=0.02854gH$

3. Calculate the mass of O by difference

$0.519g-0.3384g-0.02854g=0.15206g$

4. Convert every mass to number of moles:

C: 0.3384g / (12.011g/mol) = 0.02817 mol

H: 0.02854g / (1.008g/mol) = 0.02831 mol

O: 0.15206g / (15.999g/mol) = 0.009504 mol

5. Divide every number of moles by the least number of moles (0.009504):

C: 0.02817/0.009504 = 2.96 ≈ 3

H: 0.02831 / 0.009504 ≈ 3

O: 0.009504 / 0.009504 = 1

6. Those numbers are the respective subscripts in the empirical formula:

$C_3H_3O$

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3 years ago

Name the following compound:

Tems11 [23]

Answer:

The answer is 1-butene

Explanation:

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4 years ago

The process by which plants give off water vapor into the air is

kaheart [24]

Answer:transpiration

Explanation:

The water eventually is released to the atmosphere as vapor via the plant's stomata — tiny, closeable, pore-like structures on the surfaces of leaves. Overall, this uptake of water at the roots, transport of water through plant tissues, and release of vapor by leaves is known as transpiration.

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3 years ago