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Afina-wow [57]
3 years ago
9

When studying atoms, scientists can ignore the ______ force between charged particles that make up the atoms because it is many

millions of times smaller than other forces in the atom.
Gravitational
Constant
Normal
Fricitional
Physics
2 answers:
MArishka [77]3 years ago
6 0

Answer:

Gravitational

Explanation:

When studying atoms, scientists can ignore the  gravitational force between charged particles that make up the atoms because it is many millions of times smaller than other forces in the atom.

Reptile [31]3 years ago
4 0

Answer:

Gravitational

Explanation:

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1/8 = (1/2)^3

This implies the sample has decayed for 3 half lives

3 * 5730 yrs = 17,200 years

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what will happen to the brightness of the other bulbs in a series circuit if any of the bulbs were to burn out?
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not work.

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Define an expression for linear expansion of solid​
Vesnalui [34]

\huge \tt \underline \red{answer}

When something is heated or cooled, its length changes by an amount proportional to the original length and the change in temperature: linear expansion : ΔL=αL0ΔT (α is the coefficient of linear expansion) The coefficient of linear expansion depends only on the material an object is made from.

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4 0
2 years ago
How does momentum play in tackling?
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5 0
3 years ago
A radar station detects an airplane approaching directly from the east. At first observation, the range to the plane is 375.0 m
Gekata [30.6K]

Answer:

819.78 m

Explanation:

<u>Given:</u>

  • OA = range of initial position of the airplane from the point of observation = 375 m
  • OB = range of the final position of the airplane from the point of observation = 797 m
  • \theta = angle of the initial position vector from the observation point = 43^\circ
  • \alpha = angle of the final position vector from the observation point = 123^\circ
  • \vec{AB} = displacement vector from initial position to the final position

A diagram has been attached with the solution in order to clearly show the position of the plane.

\vec{OA} = OA\cos \theta \hat{i}+OA \sin \theta \hat{j}\\\Rightarrow \vec{OA} = 375\ m\cos 43^\circ \hat{i}+375\ m\sin 43^\circ \hat{j}\\\Rightarrow \vec{OA} = (274.26\ \hat{i}+255.75\ \hat{j})\ m\\\vec{OB} = OB\cos \alpha \hat{i}+OB \sin \alpha \hat{j}\\\Rightarrow \vec{OB} = 797\ m\cos 123^\circ \hat{i}+797\ m\sin 123^\circ \hat{j}\\\Rightarrow \vec{OB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

\vec{AB}=\vec{OB}-\vec{OA}\\\Rightarrow \vec{AB} =  (-434.08\ \hat{i}+668.42\ \hat{j})\ m-(274.26\ \hat{i}+255.75\ \hat{j})\ m\\\Rightarrow \vec{AB} =  (-708.34\ \hat{i}+412.67\ \hat{j})\ m

The magnitude of the displacement vector = \sqrt{(-708.34)^2+(412.67)^2}\ m = 819.78\ m

Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.

8 0
3 years ago
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