B. A gram would have a lot more molecules of propane than a mole
Answer:
If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.
Explanation:
Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure
V ∝ 1/P or V₁·P₁ = V₂·P₂
Where:
V₁ = Initial volume
V₂ = Final volume = V₁/2
P₁ = Initial pressure = 832 torr
P₂ = Final pressure = Required
From V₁·P₁ = V₂·P₂ we have,
P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)
P₂ = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr
NaCl + H2O = HCl + NaOH
FIRST write the equation and balance the equation THEN convert the volume of the gas to moles of the gas PV=nRT THEN according to the stoichiometry of the reaction one mol of gas is produced by one mol of salt. Convert the mol of gas to mol of salt FINALLY calculate the molar mass of the salt and convert the mol of salt to g of salt (m= nxMM)
