The volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .
<h3>Weight of one gallon of water</h3>
The weight of 1 gal of water is given as 3785 g
Mass of 8.48 x 10⁸ gal = 3785 x 8.48 x 10⁸ = 3.2 x 10¹² g
<h3>Volume of the water in cubic meters</h3>
Volume = mass/density
Volume = 3.2 x 10¹² g/1 gmL
Volume = 3.2 x 10¹² mL x 10⁻⁶ m³/mL = 3.2 x 10⁶ m³
Thus, the volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .
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Answer:oxygen Explanation:The medical condition described here is anaemia. It is a blood cell disorder whereby the red blood cell doesn't function properly and hence doesn't carry enough oxygen to the tissues. This is usually caused when ones body is deficient of iron.The symptoms that may occur to such patients are weakness, fatigue, headache and pale skin.Based on the explanation, the answer is oxygen
Explanation:
A.genetic modification of food helps it grow more easily in certain areas
Explanation:
The statement genetic modification of food helps it grow more easily in certain areas is a form of agricultural research that is very accurate.
Genetically modifying food is common practice in order to encourage desirable and sustainable traits in plant species.
- Drought resistant breeds can tolerate a much lower level of water in some specific areas.
- Disease resistant breeds are more adapted to outbreaks of plant epidemics.
- Overall, genetic modification of food helps them to grow and produce better.
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I would agree with the second one, not the first. You can't always see the chemical reaction, and it isn't always sudden. But the second claim is true.
Answer:
8.73
Explanation:
The concentration of acetic acid can be determined as follows:
Moles of 
= 
=0.0090 moles
Moles of 
= 0.0090 moles
The equation for the reaction can be expressed as :
-----> 
Concentration of 
ion = 
= 
= 0.052 M
Hydrolysis of ion:
-----> 
⇒ 
= 
As K is so less, then x appears to be a very infinitesimal small number
0.052-x ≅ x
![[OH] = x =0.535*10^{-5}](https://tex.z-dn.net/?f=%5BOH%5D%20%3D%20x%20%3D0.535%2A10%5E%7B-5%7D)
![pOH = -log[OH^-]](https://tex.z-dn.net/?f=pOH%20%3D%20-log%5BOH%5E-%5D)
![pOH = -log[0.535*10^{-5}]](https://tex.z-dn.net/?f=pOH%20%3D%20-log%5B0.535%2A10%5E%7B-5%7D%5D)
pH = 14 - pOH
pH = 14 - 5.27
pH = 8.73
Hence, the pH of the titration mixture = 8.73
